Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹50200 at 20% per year for 2 years (in ₹)?
- 2.A scooter is worth ₹55200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 3.Find the compound interest on ₹46000 at 25% per year for 2 years, compounded every year (in ₹).
- 4.A town has 5200 people. The population grows by 25% every year. What will the population be after 2 years?
- 5.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
- 6.What amount will ₹11200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 7.What amount will ₹17200 grow to in 1 year at 10% per year compound interest (in ₹)?
- 8.A scooter is worth ₹56300. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 9.What amount will ₹37700 grow to in 1 year at 25% per year compound interest (in ₹)?
- 10.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
- 11.A scooter is worth ₹7500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 12.Find the compound interest on ₹44000 at 10% per year for 3 years, compounded every year (in ₹).
- 13.Find the compound interest on ₹49600 at 25% per year for 2 years, compounded every year (in ₹).
- 14.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
- 15.What amount will ₹17500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
- 17.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 18.What amount will ₹15000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 19.A scooter is worth ₹52200. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 20.What amount will ₹43600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 21.Find the compound interest on ₹39800 at 25% per year for 1 year, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹55600 at 15% per year for 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹24400 at 5% per year for 2 years (in ₹)?
- 24.What amount will ₹56100 grow to in 1 year at 5% per year compound interest (in ₹)?
- 25.What amount will ₹2700 grow to in 1 year at 20% per year compound interest (in ₹)?
- 26.A town has 37500 people. The population grows by 8% every year. What will the population be after 2 years?
- 27.A town has 20100 people. The population grows by 10% every year. What will the population be after 2 years?
- 28.What amount will ₹9900 grow to in 1 year at 4% per year compound interest (in ₹)?
- 29.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
- 30.A town has 52300 people. The population grows by 20% every year. What will the population be after 2 years?
- 31.What is the difference between the compound interest and the simple interest on ₹53300 at 10% per year for 2 years (in ₹)?
- 32.Find the compound interest on ₹29300 at 10% per year for 1 year, compounded every year (in ₹).
- 33.What is the difference between the compound interest and the simple interest on ₹56400 at 5% per year for 2 years (in ₹)?
- 34.A scooter is worth ₹57600. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 35.Find the compound interest on ₹37500 at 4% per year for 2 years, compounded every year (in ₹).
- 36.What amount will ₹46000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 37.A scooter is worth ₹34400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
- 38.What amount will ₹17500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 39.Find the compound interest on ₹42100 at 8% per year for 1 year, compounded every year (in ₹).
- 40.A town has 16300 people. The population grows by 4% every year. What will the population be after 1 year?
Answer key
- 2008
- 52440
- 25875
- 8125
- 18522
- 21875
- 18920
- 47855
- 47125
- 25002
- 6348
- 14564
- 27900
- 73002
- 18928
- 612
- 9261
- 16224
- 50112
- 57661
- 9950
- 1251
- 61
- 58905
- 3240
- 43740
- 24321
- 10296
- 52488
- 75312
- 533
- 2930
- 141
- 46656
- 3060
- 61226
- 31648
- 20412
- 3368
- 16952
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