← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 622 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A scooter is worth ₹32000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  2. 2.A town has 51300 people. The population grows by 4% every year. What will the population be after 1 year?
  3. 3.Find the compound interest on ₹40000 at 4% per year for 2 years, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹40000 at 5% per year for 2 years (in ₹)?
  5. 5.What amount will ₹17500 grow to in 2 years at 8% per year compound interest (in ₹)?
  6. 6.What amount will ₹49600 grow to in 1 year at 12% per year compound interest (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹54200 at 20% per year for 2 years (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹19300 at 10% per year for 2 years (in ₹)?
  9. 9.What amount will ₹40400 grow to in 2 years at 10% per year compound interest (in ₹)?
  10. 10.What amount will ₹50000 grow to in 2 years at 5% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹42000 at 15% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹24200 at 20% per year for 2 years, compounded every year (in ₹).
  13. 13.What is the difference between the compound interest and the simple interest on ₹36400 at 15% per year for 2 years (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹44700 at 20% per year for 2 years (in ₹)?
  15. 15.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
  16. 16.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
  17. 17.What is the difference between the compound interest and the simple interest on ₹31100 at 10% per year for 2 years (in ₹)?
  18. 18.Find the compound interest on ₹46800 at 5% per year for 1 year, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹35800 at 12% per year for 1 year, compounded every year (in ₹).
  20. 20.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
  21. 21.What amount will ₹56000 grow to in 3 years at 25% per year compound interest (in ₹)?
  22. 22.Find the compound interest on ₹53000 at 10% per year for 3 years, compounded every year (in ₹).
  23. 23.Find the compound interest on ₹42500 at 8% per year for 2 years, compounded every year (in ₹).
  24. 24.A town has 54100 people. The population grows by 10% every year. What will the population be after 2 years?
  25. 25.What is the difference between the compound interest and the simple interest on ₹32000 at 25% per year for 2 years (in ₹)?
  26. 26.A town has 53800 people. The population grows by 15% every year. What will the population be after 1 year?
  27. 27.What amount will ₹2300 grow to in 1 year at 10% per year compound interest (in ₹)?
  28. 28.What amount will ₹34500 grow to in 2 years at 20% per year compound interest (in ₹)?
  29. 29.Find the compound interest on ₹43200 at 5% per year for 2 years, compounded every year (in ₹).
  30. 30.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹55600 at 25% per year for 2 years (in ₹)?
  32. 32.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹15000 at 20% per year for 3 years, compounded every year (in ₹).
  34. 34.What amount will ₹59000 grow to in 3 years at 20% per year compound interest (in ₹)?
  35. 35.A town has 2000 people. The population grows by 25% every year. What will the population be after 2 years?
  36. 36.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹54000 at 5% per year for 2 years (in ₹)?
  38. 38.A town has 23200 people. The population grows by 25% every year. What will the population be after 2 years?
  39. 39.Find the compound interest on ₹36300 at 25% per year for 1 year, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹44400 at 20% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 27436
  2. 53352
  3. 3264
  4. 100
  5. 20412
  6. 55552
  7. 2168
  8. 193
  9. 48884
  10. 55125
  11. 945
  12. 10648
  13. 819
  14. 1788
  15. 6305
  16. 48668
  17. 311
  18. 2340
  19. 4296
  20. 32
  21. 109375
  22. 17543
  23. 7072
  24. 65461
  25. 2000
  26. 61870
  27. 2530
  28. 49680
  29. 4428
  30. 208
  31. 3475
  32. 7566
  33. 10920
  34. 101952
  35. 3125
  36. 1261
  37. 135
  38. 36250
  39. 9075
  40. 8880

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets