Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 627 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹54000 grow to in 3 years at 10% per year compound interest (in ₹)?
2. 2.A scooter is worth ₹34800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹47500 at 8% per year for 2 years (in ₹)?
4. 4.What is the difference between the compound interest and the simple interest on ₹14700 at 10% per year for 2 years (in ₹)?
5. 5.Find the compound interest on ₹23100 at 25% per year for 1 year, compounded every year (in ₹).
6. 6.What amount will ₹51500 grow to in 1 year at 10% per year compound interest (in ₹)?
7. 7.A town has 22800 people. The population grows by 12% every year. What will the population be after 1 year?
8. 8.A scooter is worth ₹51000. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹25000 at 4% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹17300 at 25% per year for 1 year, compounded every year (in ₹).
11. 11.A scooter is worth ₹32000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
12. 12.What amount will ₹6900 grow to in 1 year at 5% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹30000 at 5% per year for 2 years (in ₹)?
14. 14.A scooter is worth ₹2500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹16000 at 25% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹6300 at 4% per year for 1 year, compounded every year (in ₹).
17. 17.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹23700 at 10% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹52000 at 10% per year for 3 years, compounded every year (in ₹).
20. 20.What amount will ₹40800 grow to in 1 year at 5% per year compound interest (in ₹)?
21. 21.A town has 10000 people. The population grows by 10% every year. What will the population be after 2 years?
22. 22.What amount will ₹28000 grow to in 3 years at 10% per year compound interest (in ₹)?
23. 23.What amount will ₹11500 grow to in 2 years at 20% per year compound interest (in ₹)?
24. 24.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹2500 at 20% per year for 1 year, compounded every year (in ₹).
26. 26.A scooter is worth ₹43900. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
27. 27.Find the compound interest on ₹59800 at 20% per year for 1 year, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹17500 at 10% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹2600 at 20% per year for 2 years, compounded every year (in ₹).
30. 30.A scooter is worth ₹23200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹54400 at 5% per year for 2 years (in ₹)?
32. 32.A town has 19400 people. The population grows by 25% every year. What will the population be after 1 year?
33. 33.A town has 10500 people. The population grows by 4% every year. What will the population be after 1 year?
34. 34.What is the difference between the compound interest and the simple interest on ₹58300 at 10% per year for 2 years (in ₹)?
35. 35.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
36. 36.A scooter is worth ₹53600. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
37. 37.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹51600 at 15% per year for 2 years, compounded every year (in ₹).
39. 39.A town has 42000 people. The population grows by 25% every year. What will the population be after 2 years?
40. 40.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?

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