Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 633 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹14800 at 5% per year for 2 years (in ₹)?
2. 2.A scooter is worth ₹47900. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
3. 3.A scooter is worth ₹38900. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
4. 4.What amount will ₹20000 grow to in 3 years at 20% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹12800 at 25% per year for 3 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹48000 at 10% per year for 3 years, compounded every year (in ₹).
7. 7.Find the compound interest on ₹57200 at 20% per year for 2 years, compounded every year (in ₹).
8. 8.What amount will ₹16300 grow to in 1 year at 8% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
10. 10.What amount will ₹37200 grow to in 2 years at 25% per year compound interest (in ₹)?
11. 11.Find the compound interest on ₹12000 at 10% per year for 1 year, compounded every year (in ₹).
12. 12.Find the compound interest on ₹38400 at 25% per year for 3 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹7500 at 12% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
15. 15.What amount will ₹47500 grow to in 2 years at 8% per year compound interest (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹40000 at 15% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹14400 at 5% per year for 1 year, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹17200 at 15% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹45300 at 15% per year for 1 year, compounded every year (in ₹).
20. 20.What amount will ₹4400 grow to in 2 years at 10% per year compound interest (in ₹)?
21. 21.Find the compound interest on ₹20300 at 12% per year for 1 year, compounded every year (in ₹).
22. 22.What is the difference between the compound interest and the simple interest on ₹22400 at 5% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
25. 25.Find the compound interest on ₹27700 at 25% per year for 1 year, compounded every year (in ₹).
26. 26.What amount will ₹39700 grow to in 1 year at 4% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹24500 at 12% per year for 1 year, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹13600 at 15% per year for 2 years (in ₹)?
29. 29.What amount will ₹32800 grow to in 1 year at 12% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹14600 at 8% per year for 1 year, compounded every year (in ₹).
31. 31.What amount will ₹25900 grow to in 1 year at 4% per year compound interest (in ₹)?
32. 32.A scooter is worth ₹13200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
33. 33.What amount will ₹2500 grow to in 2 years at 12% per year compound interest (in ₹)?
34. 34.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
35. 35.What amount will ₹3700 grow to in 1 year at 8% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
37. 37.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
38. 38.A town has 24000 people. The population grows by 15% every year. What will the population be after 3 years?
39. 39.Find the compound interest on ₹53000 at 10% per year for 3 years, compounded every year (in ₹).
40. 40.A town has 2000 people. The population grows by 5% every year. What will the population be after 2 years?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets