Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 638 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹19200 at 25% per year for 2 years (in ₹)?
2. 2.What amount will ₹53800 grow to in 1 year at 10% per year compound interest (in ₹)?
3. 3.A town has 18500 people. The population grows by 5% every year. What will the population be after 1 year?
4. 4.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
6. 6.Find the compound interest on ₹1600 at 25% per year for 3 years, compounded every year (in ₹).
7. 7.What amount will ₹26700 grow to in 2 years at 10% per year compound interest (in ₹)?
8. 8.Find the compound interest on ₹33600 at 25% per year for 3 years, compounded every year (in ₹).
9. 9.What amount will ₹58600 grow to in 2 years at 10% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹32000 at 25% per year for 3 years, compounded every year (in ₹).
11. 11.A town has 21800 people. The population grows by 20% every year. What will the population be after 2 years?
12. 12.A scooter is worth ₹55000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
13. 13.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
14. 14.What amount will ₹17500 grow to in 2 years at 10% per year compound interest (in ₹)?
15. 15.A scooter is worth ₹6800. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
17. 17.A scooter is worth ₹13500. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
18. 18.What amount will ₹5000 grow to in 2 years at 4% per year compound interest (in ₹)?
19. 19.A town has 25000 people. The population grows by 12% every year. What will the population be after 2 years?
20. 20.What amount will ₹49900 grow to in 1 year at 15% per year compound interest (in ₹)?
21. 21.A town has 31900 people. The population grows by 15% every year. What will the population be after 1 year?
22. 22.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
23. 23.What amount will ₹34400 grow to in 2 years at 25% per year compound interest (in ₹)?
24. 24.Find the compound interest on ₹23000 at 20% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹22300 at 10% per year for 1 year, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹12000 at 15% per year for 2 years (in ₹)?
27. 27.A scooter is worth ₹55000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
28. 28.What amount will ₹18000 grow to in 1 year at 20% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹10000 at 4% per year for 2 years, compounded every year (in ₹).
30. 30.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹26900 at 20% per year for 2 years (in ₹)?
33. 33.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹59600 at 15% per year for 2 years (in ₹)?
35. 35.A town has 4000 people. The population grows by 10% every year. What will the population be after 1 year?
36. 36.Find the compound interest on ₹17100 at 10% per year for 2 years, compounded every year (in ₹).
37. 37.What amount will ₹24000 grow to in 2 years at 5% per year compound interest (in ₹)?
38. 38.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹39700 at 20% per year for 2 years (in ₹)?
40. 40.A scooter is worth ₹47500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?

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