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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 644 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹33600 grow to in 2 years at 5% per year compound interest (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹34500 at 20% per year for 2 years (in ₹)?
  3. 3.Find the compound interest on ₹29700 at 20% per year for 2 years, compounded every year (in ₹).
  4. 4.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
  5. 5.What is the difference between the compound interest and the simple interest on ₹14000 at 10% per year for 2 years (in ₹)?
  6. 6.What is the difference between the compound interest and the simple interest on ₹6800 at 15% per year for 2 years (in ₹)?
  7. 7.Find the compound interest on ₹10900 at 8% per year for 1 year, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹24200 at 20% per year for 2 years (in ₹)?
  9. 9.Find the compound interest on ₹45200 at 15% per year for 1 year, compounded every year (in ₹).
  10. 10.What is the difference between the compound interest and the simple interest on ₹11700 at 10% per year for 2 years (in ₹)?
  11. 11.What amount will ₹25000 grow to in 2 years at 12% per year compound interest (in ₹)?
  12. 12.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
  13. 13.A scooter is worth ₹35500. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  14. 14.What is the difference between the compound interest and the simple interest on ₹20900 at 10% per year for 2 years (in ₹)?
  15. 15.A scooter is worth ₹52200. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
  16. 16.What amount will ₹50000 grow to in 2 years at 10% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹58000 at 4% per year for 1 year, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
  19. 19.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
  20. 20.A scooter is worth ₹12000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹58400 at 5% per year for 2 years (in ₹)?
  22. 22.Find the compound interest on ₹30800 at 8% per year for 1 year, compounded every year (in ₹).
  23. 23.A town has 10000 people. The population grows by 12% every year. What will the population be after 2 years?
  24. 24.What amount will ₹41700 grow to in 2 years at 10% per year compound interest (in ₹)?
  25. 25.A scooter is worth ₹23900. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  26. 26.A town has 31600 people. The population grows by 20% every year. What will the population be after 2 years?
  27. 27.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
  28. 28.What is the difference between the compound interest and the simple interest on ₹30000 at 4% per year for 2 years (in ₹)?
  29. 29.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
  30. 30.Find the compound interest on ₹21100 at 25% per year for 1 year, compounded every year (in ₹).
  31. 31.Find the compound interest on ₹54100 at 10% per year for 1 year, compounded every year (in ₹).
  32. 32.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
  33. 33.A town has 40000 people. The population grows by 5% every year. What will the population be after 3 years?
  34. 34.What is the difference between the compound interest and the simple interest on ₹37600 at 25% per year for 2 years (in ₹)?
  35. 35.What is the difference between the compound interest and the simple interest on ₹40000 at 5% per year for 2 years (in ₹)?
  36. 36.A town has 37500 people. The population grows by 12% every year. What will the population be after 2 years?
  37. 37.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹15600 at 10% per year for 2 years, compounded every year (in ₹).
  39. 39.Find the compound interest on ₹17500 at 4% per year for 2 years, compounded every year (in ₹).
  40. 40.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 37044
  2. 1380
  3. 13068
  4. 4452
  5. 140
  6. 153
  7. 872
  8. 968
  9. 6780
  10. 117
  11. 31360
  12. 648
  13. 31240
  14. 209
  15. 33408
  16. 60500
  17. 2320
  18. 288
  19. 8736
  20. 8748
  21. 146
  22. 2464
  23. 12544
  24. 50457
  25. 21510
  26. 45504
  27. 25002
  28. 48
  29. 48668
  30. 5275
  31. 5410
  32. 5044
  33. 46305
  34. 2350
  35. 100
  36. 47040
  37. 96
  38. 3276
  39. 1428
  40. 7904

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