Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What amount will ₹4600 grow to in 1 year at 10% per year compound interest (in ₹)?
- 2.Find the compound interest on ₹33000 at 20% per year for 3 years, compounded every year (in ₹).
- 3.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 4.What amount will ₹32600 grow to in 1 year at 12% per year compound interest (in ₹)?
- 5.What amount will ₹55400 grow to in 1 year at 20% per year compound interest (in ₹)?
- 6.What amount will ₹58000 grow to in 2 years at 5% per year compound interest (in ₹)?
- 7.A town has 37500 people. The population grows by 8% every year. What will the population be after 2 years?
- 8.Find the compound interest on ₹12400 at 20% per year for 2 years, compounded every year (in ₹).
- 9.What amount will ₹3600 grow to in 1 year at 10% per year compound interest (in ₹)?
- 10.What is the difference between the compound interest and the simple interest on ₹52400 at 15% per year for 2 years (in ₹)?
- 11.A town has 21900 people. The population grows by 12% every year. What will the population be after 1 year?
- 12.A scooter is worth ₹54700. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 13.A town has 5000 people. The population grows by 10% every year. What will the population be after 3 years?
- 14.Find the compound interest on ₹3600 at 10% per year for 1 year, compounded every year (in ₹).
- 15.A town has 7600 people. The population grows by 5% every year. What will the population be after 2 years?
- 16.What amount will ₹37000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 17.What amount will ₹19200 grow to in 2 years at 15% per year compound interest (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹51000 at 10% per year for 2 years (in ₹)?
- 19.Find the compound interest on ₹51500 at 20% per year for 3 years, compounded every year (in ₹).
- 20.What is the difference between the compound interest and the simple interest on ₹47500 at 12% per year for 2 years (in ₹)?
- 21.What amount will ₹29600 grow to in 1 year at 12% per year compound interest (in ₹)?
- 22.Find the compound interest on ₹52200 at 4% per year for 1 year, compounded every year (in ₹).
- 23.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
- 24.Find the compound interest on ₹47800 at 12% per year for 1 year, compounded every year (in ₹).
- 25.What amount will ₹9200 grow to in 2 years at 15% per year compound interest (in ₹)?
- 26.What amount will ₹57500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 27.What amount will ₹15600 grow to in 1 year at 8% per year compound interest (in ₹)?
- 28.What amount will ₹4700 grow to in 1 year at 12% per year compound interest (in ₹)?
- 29.What amount will ₹4800 grow to in 1 year at 25% per year compound interest (in ₹)?
- 30.Find the compound interest on ₹48000 at 10% per year for 3 years, compounded every year (in ₹).
- 31.A town has 30000 people. The population grows by 12% every year. What will the population be after 2 years?
- 32.What amount will ₹56600 grow to in 1 year at 4% per year compound interest (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹58400 at 20% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹16000 at 15% per year for 3 years, compounded every year (in ₹).
- 36.A town has 56900 people. The population grows by 20% every year. What will the population be after 2 years?
- 37.What amount will ₹11700 grow to in 1 year at 10% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹52100 at 4% per year for 1 year, compounded every year (in ₹).
- 39.Find the compound interest on ₹7700 at 20% per year for 1 year, compounded every year (in ₹).
- 40.A town has 11400 people. The population grows by 10% every year. What will the population be after 2 years?
Answer key
- 5060
- 24024
- 7566
- 36512
- 66480
- 63945
- 43740
- 5456
- 3960
- 1179
- 24528
- 52512
- 6655
- 360
- 8379
- 63936
- 25392
- 510
- 37492
- 684
- 33152
- 2088
- 12501
- 5736
- 12167
- 62192
- 16848
- 5264
- 6000
- 15888
- 37632
- 58864
- 128
- 2336
- 8334
- 81936
- 12870
- 2084
- 1540
- 13794
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