Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
- 2.What is the difference between the compound interest and the simple interest on ₹57500 at 8% per year for 2 years (in ₹)?
- 3.Find the compound interest on ₹2200 at 10% per year for 1 year, compounded every year (in ₹).
- 4.What amount will ₹30400 grow to in 3 years at 25% per year compound interest (in ₹)?
- 5.What amount will ₹15600 grow to in 2 years at 15% per year compound interest (in ₹)?
- 6.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
- 7.Find the compound interest on ₹38600 at 25% per year for 1 year, compounded every year (in ₹).
- 8.What amount will ₹45000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 9.Find the compound interest on ₹57000 at 5% per year for 1 year, compounded every year (in ₹).
- 10.What amount will ₹28000 grow to in 1 year at 8% per year compound interest (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
- 12.Find the compound interest on ₹5600 at 5% per year for 2 years, compounded every year (in ₹).
- 13.What is the difference between the compound interest and the simple interest on ₹14400 at 10% per year for 2 years (in ₹)?
- 14.A town has 41300 people. The population grows by 20% every year. What will the population be after 1 year?
- 15.A scooter is worth ₹56000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 16.A town has 52700 people. The population grows by 15% every year. What will the population be after 1 year?
- 17.What is the difference between the compound interest and the simple interest on ₹56400 at 25% per year for 2 years (in ₹)?
- 18.What amount will ₹12800 grow to in 1 year at 15% per year compound interest (in ₹)?
- 19.Find the compound interest on ₹48400 at 15% per year for 2 years, compounded every year (in ₹).
- 20.What amount will ₹4300 grow to in 1 year at 20% per year compound interest (in ₹)?
- 21.Find the compound interest on ₹37900 at 15% per year for 1 year, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹14600 at 20% per year for 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹36400 at 25% per year for 2 years (in ₹)?
- 24.Find the compound interest on ₹2500 at 8% per year for 2 years, compounded every year (in ₹).
- 25.Find the compound interest on ₹31200 at 8% per year for 1 year, compounded every year (in ₹).
- 26.Find the compound interest on ₹41300 at 10% per year for 2 years, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹10000 at 10% per year for 2 years (in ₹)?
- 28.What is the difference between the compound interest and the simple interest on ₹26300 at 20% per year for 2 years (in ₹)?
- 29.A scooter is worth ₹7700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 30.A scooter is worth ₹25000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 31.A town has 23000 people. The population grows by 10% every year. What will the population be after 2 years?
- 32.What amount will ₹51000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 33.A town has 25800 people. The population grows by 20% every year. What will the population be after 1 year?
- 34.What amount will ₹34700 grow to in 2 years at 10% per year compound interest (in ₹)?
- 35.A scooter is worth ₹7400. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
- 36.Find the compound interest on ₹12500 at 4% per year for 2 years, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹57200 at 5% per year for 2 years (in ₹)?
- 38.Find the compound interest on ₹26100 at 8% per year for 1 year, compounded every year (in ₹).
- 39.What amount will ₹22000 grow to in 1 year at 25% per year compound interest (in ₹)?
- 40.Find the compound interest on ₹58400 at 5% per year for 2 years, compounded every year (in ₹).
Answer key
- 55566
- 368
- 220
- 59375
- 20631
- 208
- 9650
- 48672
- 2850
- 30240
- 28
- 574
- 144
- 49560
- 34391
- 60605
- 3525
- 14720
- 15609
- 5160
- 5685
- 584
- 2275
- 416
- 2496
- 8673
- 100
- 1052
- 7315
- 21160
- 27830
- 67881
- 30960
- 41987
- 4736
- 1020
- 143
- 2088
- 27500
- 5986
Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets