Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 652 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
2. 2.A town has 37800 people. The population grows by 4% every year. What will the population be after 1 year?
3. 3.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹60000 at 5% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
7. 7.A town has 35200 people. The population grows by 25% every year. What will the population be after 3 years?
8. 8.Find the compound interest on ₹47000 at 10% per year for 3 years, compounded every year (in ₹).
9. 9.Find the compound interest on ₹5000 at 8% per year for 2 years, compounded every year (in ₹).
10. 10.What amount will ₹32400 grow to in 2 years at 20% per year compound interest (in ₹)?
11. 11.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
13. 13.A scooter is worth ₹20400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
14. 14.A scooter is worth ₹20200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
15. 15.What amount will ₹20800 grow to in 2 years at 5% per year compound interest (in ₹)?
16. 16.What amount will ₹57500 grow to in 2 years at 4% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
18. 18.Find the compound interest on ₹12500 at 4% per year for 2 years, compounded every year (in ₹).
19. 19.A scooter is worth ₹42500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
20. 20.Find the compound interest on ₹50000 at 4% per year for 2 years, compounded every year (in ₹).
21. 21.A scooter is worth ₹50000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
22. 22.A town has 29700 people. The population grows by 12% every year. What will the population be after 1 year?
23. 23.Find the compound interest on ₹6800 at 10% per year for 1 year, compounded every year (in ₹).
24. 24.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹56900 at 20% per year for 2 years (in ₹)?
26. 26.Find the compound interest on ₹42500 at 4% per year for 2 years, compounded every year (in ₹).
27. 27.What amount will ₹17000 grow to in 3 years at 10% per year compound interest (in ₹)?
28. 28.A scooter is worth ₹45000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹38800 at 5% per year for 2 years (in ₹)?
30. 30.A town has 6100 people. The population grows by 5% every year. What will the population be after 1 year?
31. 31.What amount will ₹40000 grow to in 2 years at 4% per year compound interest (in ₹)?
32. 32.A town has 32500 people. The population grows by 4% every year. What will the population be after 2 years?
33. 33.What amount will ₹28000 grow to in 1 year at 12% per year compound interest (in ₹)?
34. 34.What amount will ₹27800 grow to in 2 years at 10% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹11000 at 10% per year for 3 years, compounded every year (in ₹).
36. 36.A town has 31200 people. The population grows by 25% every year. What will the population be after 1 year?
37. 37.What is the difference between the compound interest and the simple interest on ₹53000 at 10% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
39. 39.What amount will ₹6900 grow to in 1 year at 5% per year compound interest (in ₹)?
40. 40.A town has 40700 people. The population grows by 15% every year. What will the population be after 1 year?

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