Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 654 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹19500 at 20% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹6400 at 5% per year for 2 years (in ₹)?
3. 3.A scooter is worth ₹12400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
4. 4.A scooter is worth ₹10000. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
5. 5.A town has 59000 people. The population grows by 10% every year. What will the population be after 3 years?
6. 6.What amount will ₹36000 grow to in 3 years at 10% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹15000 at 10% per year for 2 years, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹45000 at 12% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹5000 at 12% per year for 2 years, compounded every year (in ₹).
10. 10.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹20000 at 8% per year for 2 years, compounded every year (in ₹).
12. 12.A scooter is worth ₹48900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
13. 13.A town has 15000 people. The population grows by 8% every year. What will the population be after 2 years?
14. 14.What amount will ₹15600 grow to in 1 year at 10% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹10000 at 8% per year for 2 years (in ₹)?
16. 16.A town has 27500 people. The population grows by 12% every year. What will the population be after 2 years?
17. 17.What amount will ₹12800 grow to in 1 year at 12% per year compound interest (in ₹)?
18. 18.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
19. 19.A town has 32500 people. The population grows by 12% every year. What will the population be after 2 years?
20. 20.Find the compound interest on ₹32200 at 20% per year for 1 year, compounded every year (in ₹).
21. 21.A scooter is worth ₹2300. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
22. 22.Find the compound interest on ₹35300 at 4% per year for 1 year, compounded every year (in ₹).
23. 23.A town has 9100 people. The population grows by 10% every year. What will the population be after 1 year?
24. 24.A town has 32500 people. The population grows by 4% every year. What will the population be after 2 years?
25. 25.Find the compound interest on ₹26800 at 8% per year for 1 year, compounded every year (in ₹).
26. 26.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
27. 27.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
28. 28.A town has 18300 people. The population grows by 10% every year. What will the population be after 2 years?
29. 29.A scooter is worth ₹17100. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹15200 at 25% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹4200 at 20% per year for 1 year, compounded every year (in ₹).
32. 32.A town has 33200 people. The population grows by 5% every year. What will the population be after 1 year?
33. 33.A scooter is worth ₹6400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
34. 34.Find the compound interest on ₹20400 at 5% per year for 2 years, compounded every year (in ₹).
35. 35.A town has 17200 people. The population grows by 12% every year. What will the population be after 1 year?
36. 36.A town has 22500 people. The population grows by 8% every year. What will the population be after 2 years?
37. 37.What amount will ₹10000 grow to in 2 years at 4% per year compound interest (in ₹)?
38. 38.A scooter is worth ₹9300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
39. 39.Find the compound interest on ₹34800 at 15% per year for 2 years, compounded every year (in ₹).
40. 40.A scooter is worth ₹4200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?

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