Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 660 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹37500 at 8% per year for 2 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹53500 at 10% per year for 2 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
6. 6.A town has 35200 people. The population grows by 25% every year. What will the population be after 2 years?
7. 7.What is the difference between the compound interest and the simple interest on ₹10800 at 15% per year for 2 years (in ₹)?
8. 8.Find the compound interest on ₹27000 at 20% per year for 3 years, compounded every year (in ₹).
9. 9.What amount will ₹55800 grow to in 2 years at 10% per year compound interest (in ₹)?
10. 10.What amount will ₹53500 grow to in 3 years at 20% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹32400 at 15% per year for 2 years (in ₹)?
12. 12.Find the compound interest on ₹25600 at 25% per year for 3 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
14. 14.What amount will ₹7500 grow to in 2 years at 8% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹12800 at 25% per year for 2 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹52800 at 25% per year for 3 years, compounded every year (in ₹).
17. 17.What amount will ₹25000 grow to in 2 years at 12% per year compound interest (in ₹)?
18. 18.A scooter is worth ₹51300. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹32800 at 5% per year for 2 years (in ₹)?
20. 20.A town has 12600 people. The population grows by 10% every year. What will the population be after 1 year?
21. 21.Find the compound interest on ₹5200 at 25% per year for 2 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹20100 at 15% per year for 1 year, compounded every year (in ₹).
23. 23.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
24. 24.What is the difference between the compound interest and the simple interest on ₹26400 at 20% per year for 2 years (in ₹)?
25. 25.What amount will ₹30800 grow to in 2 years at 25% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹58800 at 15% per year for 2 years (in ₹)?
27. 27.What amount will ₹5000 grow to in 2 years at 8% per year compound interest (in ₹)?
28. 28.A town has 36400 people. The population grows by 15% every year. What will the population be after 2 years?
29. 29.Find the compound interest on ₹56000 at 20% per year for 3 years, compounded every year (in ₹).
30. 30.What amount will ₹36000 grow to in 3 years at 20% per year compound interest (in ₹)?
31. 31.A scooter is worth ₹59600. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹32800 at 5% per year for 2 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹50500 at 20% per year for 1 year, compounded every year (in ₹).
35. 35.A town has 42300 people. The population grows by 25% every year. What will the population be after 1 year?
36. 36.What is the difference between the compound interest and the simple interest on ₹22800 at 10% per year for 2 years (in ₹)?
37. 37.A town has 13200 people. The population grows by 15% every year. What will the population be after 2 years?
38. 38.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
39. 39.A scooter is worth ₹42600. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?

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