Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 662 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹6400. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
2. 2.What amount will ₹2500 grow to in 3 years at 20% per year compound interest (in ₹)?
3. 3.A town has 53600 people. The population grows by 10% every year. What will the population be after 2 years?
4. 4.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
5. 5.What amount will ₹4500 grow to in 1 year at 10% per year compound interest (in ₹)?
6. 6.A town has 20800 people. The population grows by 15% every year. What will the population be after 1 year?
7. 7.Find the compound interest on ₹11100 at 8% per year for 1 year, compounded every year (in ₹).
8. 8.What amount will ₹33600 grow to in 3 years at 25% per year compound interest (in ₹)?
9. 9.What amount will ₹19800 grow to in 1 year at 5% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹23000 at 10% per year for 3 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹17500 at 4% per year for 2 years (in ₹)?
12. 12.What amount will ₹25600 grow to in 3 years at 25% per year compound interest (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹58000 at 25% per year for 2 years (in ₹)?
14. 14.What amount will ₹41300 grow to in 1 year at 15% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
16. 16.A town has 36300 people. The population grows by 15% every year. What will the population be after 1 year?
17. 17.What is the difference between the compound interest and the simple interest on ₹15100 at 10% per year for 2 years (in ₹)?
18. 18.What amount will ₹18800 grow to in 1 year at 15% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹18000 at 10% per year for 3 years, compounded every year (in ₹).
20. 20.A town has 59200 people. The population grows by 12% every year. What will the population be after 1 year?
21. 21.A town has 4700 people. The population grows by 25% every year. What will the population be after 1 year?
22. 22.Find the compound interest on ₹2800 at 25% per year for 2 years, compounded every year (in ₹).
23. 23.A town has 47600 people. The population grows by 5% every year. What will the population be after 1 year?
24. 24.A town has 17500 people. The population grows by 4% every year. What will the population be after 2 years?
25. 25.A town has 2500 people. The population grows by 8% every year. What will the population be after 2 years?
26. 26.Find the compound interest on ₹31700 at 12% per year for 1 year, compounded every year (in ₹).
27. 27.A town has 31700 people. The population grows by 5% every year. What will the population be after 1 year?
28. 28.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹10700 at 25% per year for 1 year, compounded every year (in ₹).
30. 30.Find the compound interest on ₹17400 at 20% per year for 1 year, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹38100 at 10% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹45000 at 8% per year for 2 years, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹35600 at 5% per year for 2 years (in ₹)?
34. 34.Find the compound interest on ₹20000 at 4% per year for 2 years, compounded every year (in ₹).
35. 35.What is the difference between the compound interest and the simple interest on ₹39300 at 20% per year for 2 years (in ₹)?
36. 36.Find the compound interest on ₹59000 at 10% per year for 3 years, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹23600 at 15% per year for 2 years (in ₹)?
38. 38.What amount will ₹55600 grow to in 2 years at 10% per year compound interest (in ₹)?
39. 39.A scooter is worth ₹31600. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹15800 at 20% per year for 2 years (in ₹)?

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