← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 666 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹58100 grow to in 2 years at 10% per year compound interest (in ₹)?
  2. 2.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
  3. 3.What amount will ₹25000 grow to in 2 years at 8% per year compound interest (in ₹)?
  4. 4.A scooter is worth ₹52000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  5. 5.A town has 19100 people. The population grows by 20% every year. What will the population be after 2 years?
  6. 6.What amount will ₹12600 grow to in 1 year at 10% per year compound interest (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹9700 at 10% per year for 2 years (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹20400 at 25% per year for 2 years (in ₹)?
  10. 10.What amount will ₹52100 grow to in 1 year at 12% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹34800 at 25% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹10400 at 20% per year for 2 years, compounded every year (in ₹).
  13. 13.A scooter is worth ₹34000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  14. 14.Find the compound interest on ₹30600 at 20% per year for 1 year, compounded every year (in ₹).
  15. 15.What is the difference between the compound interest and the simple interest on ₹55900 at 10% per year for 2 years (in ₹)?
  16. 16.A scooter is worth ₹32800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  17. 17.A scooter is worth ₹54900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  18. 18.Find the compound interest on ₹21700 at 20% per year for 2 years, compounded every year (in ₹).
  19. 19.What is the difference between the compound interest and the simple interest on ₹48100 at 10% per year for 2 years (in ₹)?
  20. 20.What amount will ₹17500 grow to in 1 year at 10% per year compound interest (in ₹)?
  21. 21.A town has 35700 people. The population grows by 20% every year. What will the population be after 2 years?
  22. 22.What amount will ₹19300 grow to in 1 year at 5% per year compound interest (in ₹)?
  23. 23.A town has 52500 people. The population grows by 8% every year. What will the population be after 2 years?
  24. 24.What amount will ₹41600 grow to in 3 years at 25% per year compound interest (in ₹)?
  25. 25.A scooter is worth ₹54400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  26. 26.Find the compound interest on ₹20000 at 20% per year for 3 years, compounded every year (in ₹).
  27. 27.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
  28. 28.A scooter is worth ₹17100. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  29. 29.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
  30. 30.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  31. 31.A town has 57500 people. The population grows by 12% every year. What will the population be after 2 years?
  32. 32.What is the difference between the compound interest and the simple interest on ₹11300 at 10% per year for 2 years (in ₹)?
  33. 33.A town has 10000 people. The population grows by 4% every year. What will the population be after 2 years?
  34. 34.Find the compound interest on ₹20000 at 12% per year for 2 years, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
  36. 36.Find the compound interest on ₹41000 at 25% per year for 1 year, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹4300 at 10% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹7100 at 10% per year for 1 year, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
  40. 40.Find the compound interest on ₹51200 at 15% per year for 2 years, compounded every year (in ₹).

Answer key

  1. 70301
  2. 43740
  3. 29160
  4. 46930
  5. 27504
  6. 13860
  7. 97
  8. 384
  9. 1275
  10. 58352
  11. 2175
  12. 4576
  13. 19125
  14. 6120
  15. 559
  16. 24600
  17. 52704
  18. 9548
  19. 481
  20. 19250
  21. 51408
  22. 20265
  23. 61236
  24. 81250
  25. 39304
  26. 14560
  27. 208
  28. 16245
  29. 28224
  30. 7220
  31. 72128
  32. 113
  33. 10816
  34. 5088
  35. 36
  36. 10250
  37. 43
  38. 710
  39. 68
  40. 16512

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets