Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.What amount will ₹58100 grow to in 2 years at 10% per year compound interest (in ₹)?
- 2.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 3.What amount will ₹25000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 4.A scooter is worth ₹52000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 5.A town has 19100 people. The population grows by 20% every year. What will the population be after 2 years?
- 6.What amount will ₹12600 grow to in 1 year at 10% per year compound interest (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹9700 at 10% per year for 2 years (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹60000 at 8% per year for 2 years (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹20400 at 25% per year for 2 years (in ₹)?
- 10.What amount will ₹52100 grow to in 1 year at 12% per year compound interest (in ₹)?
- 11.What is the difference between the compound interest and the simple interest on ₹34800 at 25% per year for 2 years (in ₹)?
- 12.Find the compound interest on ₹10400 at 20% per year for 2 years, compounded every year (in ₹).
- 13.A scooter is worth ₹34000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 14.Find the compound interest on ₹30600 at 20% per year for 1 year, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹55900 at 10% per year for 2 years (in ₹)?
- 16.A scooter is worth ₹32800. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 17.A scooter is worth ₹54900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 18.Find the compound interest on ₹21700 at 20% per year for 2 years, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹48100 at 10% per year for 2 years (in ₹)?
- 20.What amount will ₹17500 grow to in 1 year at 10% per year compound interest (in ₹)?
- 21.A town has 35700 people. The population grows by 20% every year. What will the population be after 2 years?
- 22.What amount will ₹19300 grow to in 1 year at 5% per year compound interest (in ₹)?
- 23.A town has 52500 people. The population grows by 8% every year. What will the population be after 2 years?
- 24.What amount will ₹41600 grow to in 3 years at 25% per year compound interest (in ₹)?
- 25.A scooter is worth ₹54400. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 26.Find the compound interest on ₹20000 at 20% per year for 3 years, compounded every year (in ₹).
- 27.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
- 28.A scooter is worth ₹17100. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 29.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 30.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 31.A town has 57500 people. The population grows by 12% every year. What will the population be after 2 years?
- 32.What is the difference between the compound interest and the simple interest on ₹11300 at 10% per year for 2 years (in ₹)?
- 33.A town has 10000 people. The population grows by 4% every year. What will the population be after 2 years?
- 34.Find the compound interest on ₹20000 at 12% per year for 2 years, compounded every year (in ₹).
- 35.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
- 36.Find the compound interest on ₹41000 at 25% per year for 1 year, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹4300 at 10% per year for 2 years (in ₹)?
- 38.Find the compound interest on ₹7100 at 10% per year for 1 year, compounded every year (in ₹).
- 39.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
- 40.Find the compound interest on ₹51200 at 15% per year for 2 years, compounded every year (in ₹).
Answer key
- 70301
- 43740
- 29160
- 46930
- 27504
- 13860
- 97
- 384
- 1275
- 58352
- 2175
- 4576
- 19125
- 6120
- 559
- 24600
- 52704
- 9548
- 481
- 19250
- 51408
- 20265
- 61236
- 81250
- 39304
- 14560
- 208
- 16245
- 28224
- 7220
- 72128
- 113
- 10816
- 5088
- 36
- 10250
- 43
- 710
- 68
- 16512
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