Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 67 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹36800 at 20% per year for 2 years, compounded every year (in ₹).
2. 2.A scooter is worth ₹35800. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
3. 3.A town has 60000 people. The population grows by 5% every year. What will the population be after 2 years?
4. 4.Find the compound interest on ₹20000 at 5% per year for 2 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹58000 at 5% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹8400 at 5% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹34100 at 10% per year for 1 year, compounded every year (in ₹).
8. 8.Find the compound interest on ₹59600 at 25% per year for 1 year, compounded every year (in ₹).
9. 9.What is the difference between the compound interest and the simple interest on ₹15000 at 4% per year for 2 years (in ₹)?
10. 10.Find the compound interest on ₹24900 at 4% per year for 1 year, compounded every year (in ₹).
11. 11.A town has 8600 people. The population grows by 4% every year. What will the population be after 1 year?
12. 12.What is the difference between the compound interest and the simple interest on ₹22500 at 4% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹32300 at 8% per year for 1 year, compounded every year (in ₹).
14. 14.Find the compound interest on ₹5000 at 4% per year for 2 years, compounded every year (in ₹).
15. 15.What amount will ₹58400 grow to in 2 years at 25% per year compound interest (in ₹)?
16. 16.Find the compound interest on ₹48300 at 5% per year for 1 year, compounded every year (in ₹).
17. 17.A town has 36600 people. The population grows by 5% every year. What will the population be after 1 year?
18. 18.What amount will ₹6700 grow to in 1 year at 25% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹49700 at 15% per year for 1 year, compounded every year (in ₹).
20. 20.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹48900 at 20% per year for 1 year, compounded every year (in ₹).
23. 23.A town has 43000 people. The population grows by 20% every year. What will the population be after 3 years?
24. 24.What is the difference between the compound interest and the simple interest on ₹6800 at 5% per year for 2 years (in ₹)?
25. 25.What amount will ₹58500 grow to in 1 year at 5% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹37800 at 10% per year for 2 years (in ₹)?
27. 27.What amount will ₹12500 grow to in 2 years at 12% per year compound interest (in ₹)?
28. 28.Find the compound interest on ₹19500 at 10% per year for 1 year, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹2500 at 8% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹16800 at 5% per year for 2 years (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹45000 at 4% per year for 2 years (in ₹)?
32. 32.What amount will ₹39200 grow to in 1 year at 4% per year compound interest (in ₹)?
33. 33.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
34. 34.Find the compound interest on ₹12700 at 20% per year for 1 year, compounded every year (in ₹).
35. 35.A scooter is worth ₹8000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
36. 36.What amount will ₹48000 grow to in 3 years at 10% per year compound interest (in ₹)?
37. 37.What is the difference between the compound interest and the simple interest on ₹48800 at 15% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹51900 at 4% per year for 1 year, compounded every year (in ₹).
39. 39.Find the compound interest on ₹6400 at 5% per year for 2 years, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?

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