Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 671 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
2. 2.What amount will ₹41200 grow to in 1 year at 4% per year compound interest (in ₹)?
3. 3.A scooter is worth ₹2500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
4. 4.Find the compound interest on ₹12000 at 20% per year for 3 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹47200 at 5% per year for 2 years (in ₹)?
7. 7.A town has 29300 people. The population grows by 10% every year. What will the population be after 2 years?
8. 8.Find the compound interest on ₹20900 at 10% per year for 1 year, compounded every year (in ₹).
9. 9.Find the compound interest on ₹41600 at 10% per year for 1 year, compounded every year (in ₹).
10. 10.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
11. 11.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹26000 at 25% per year for 2 years (in ₹)?
13. 13.Find the compound interest on ₹43100 at 15% per year for 1 year, compounded every year (in ₹).
14. 14.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
15. 15.Find the compound interest on ₹18400 at 15% per year for 2 years, compounded every year (in ₹).
16. 16.Find the compound interest on ₹15000 at 20% per year for 2 years, compounded every year (in ₹).
17. 17.A town has 40800 people. The population grows by 10% every year. What will the population be after 1 year?
18. 18.A town has 59600 people. The population grows by 4% every year. What will the population be after 1 year?
19. 19.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹37300 at 8% per year for 1 year, compounded every year (in ₹).
21. 21.What amount will ₹49400 grow to in 1 year at 15% per year compound interest (in ₹)?
22. 22.A scooter is worth ₹28000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
24. 24.A scooter is worth ₹20000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹22300 at 10% per year for 2 years (in ₹)?
26. 26.What amount will ₹30500 grow to in 1 year at 5% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹5600 at 5% per year for 2 years, compounded every year (in ₹).
28. 28.A scooter is worth ₹26400. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹30000 at 8% per year for 2 years (in ₹)?
31. 31.What amount will ₹41300 grow to in 1 year at 8% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹57200 at 25% per year for 2 years, compounded every year (in ₹).
33. 33.What amount will ₹39000 grow to in 3 years at 20% per year compound interest (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹31200 at 20% per year for 2 years (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹11700 at 10% per year for 2 years (in ₹)?
36. 36.Find the compound interest on ₹13000 at 10% per year for 3 years, compounded every year (in ₹).
37. 37.A town has 9300 people. The population grows by 5% every year. What will the population be after 1 year?
38. 38.What is the difference between the compound interest and the simple interest on ₹31100 at 10% per year for 2 years (in ₹)?
39. 39.A scooter is worth ₹43400. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
40. 40.What amount will ₹35000 grow to in 2 years at 4% per year compound interest (in ₹)?

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