Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹6000 at 15% per year for 2 years, compounded every year (in ₹).
- 2.Find the compound interest on ₹3000 at 20% per year for 3 years, compounded every year (in ₹).
- 3.What amount will ₹20200 grow to in 1 year at 20% per year compound interest (in ₹)?
- 4.A scooter is worth ₹4000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 5.A town has 14000 people. The population grows by 10% every year. What will the population be after 1 year?
- 6.Find the compound interest on ₹45500 at 15% per year for 1 year, compounded every year (in ₹).
- 7.What amount will ₹45000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹31200 at 5% per year for 2 years (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹57600 at 5% per year for 2 years (in ₹)?
- 10.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
- 11.A scooter is worth ₹31700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 12.Find the compound interest on ₹40700 at 10% per year for 2 years, compounded every year (in ₹).
- 13.A town has 40300 people. The population grows by 10% every year. What will the population be after 2 years?
- 14.A scooter is worth ₹8000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 15.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 16.A town has 55200 people. The population grows by 25% every year. What will the population be after 2 years?
- 17.What is the difference between the compound interest and the simple interest on ₹40000 at 12% per year for 2 years (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
- 19.What amount will ₹16700 grow to in 1 year at 5% per year compound interest (in ₹)?
- 20.Find the compound interest on ₹31600 at 5% per year for 2 years, compounded every year (in ₹).
- 21.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
- 22.What is the difference between the compound interest and the simple interest on ₹2400 at 5% per year for 2 years (in ₹)?
- 23.A scooter is worth ₹10000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹38800 at 5% per year for 2 years (in ₹)?
- 25.What amount will ₹32300 grow to in 1 year at 5% per year compound interest (in ₹)?
- 26.Find the compound interest on ₹44500 at 15% per year for 1 year, compounded every year (in ₹).
- 27.Find the compound interest on ₹7000 at 5% per year for 1 year, compounded every year (in ₹).
- 28.What is the difference between the compound interest and the simple interest on ₹29000 at 20% per year for 2 years (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹44800 at 15% per year for 2 years (in ₹)?
- 30.A town has 17900 people. The population grows by 10% every year. What will the population be after 2 years?
- 31.What amount will ₹48000 grow to in 1 year at 15% per year compound interest (in ₹)?
- 32.What is the difference between the compound interest and the simple interest on ₹16000 at 5% per year for 2 years (in ₹)?
- 33.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
- 34.What amount will ₹6400 grow to in 3 years at 25% per year compound interest (in ₹)?
- 35.A town has 8400 people. The population grows by 5% every year. What will the population be after 1 year?
- 36.Find the compound interest on ₹16000 at 10% per year for 3 years, compounded every year (in ₹).
- 37.Find the compound interest on ₹3100 at 15% per year for 1 year, compounded every year (in ₹).
- 38.Find the compound interest on ₹12500 at 12% per year for 2 years, compounded every year (in ₹).
- 39.What amount will ₹56600 grow to in 2 years at 10% per year compound interest (in ₹)?
- 40.A town has 21500 people. The population grows by 25% every year. What will the population be after 1 year?
Answer key
- 1935
- 2184
- 24240
- 2916
- 15400
- 6825
- 59895
- 78
- 144
- 3783
- 28530
- 8547
- 48763
- 5832
- 64827
- 86250
- 576
- 80
- 17535
- 3239
- 144
- 6
- 8464
- 97
- 33915
- 6675
- 350
- 1160
- 1008
- 21659
- 55200
- 40
- 8827
- 12500
- 8820
- 5296
- 465
- 3180
- 68486
- 26875
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