Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 675 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹54800 at 15% per year for 2 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
3. 3.What is the difference between the compound interest and the simple interest on ₹23900 at 20% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹60000 at 4% per year for 2 years, compounded every year (in ₹).
5. 5.What amount will ₹7000 grow to in 1 year at 25% per year compound interest (in ₹)?
6. 6.A scooter is worth ₹56000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
7. 7.A town has 50400 people. The population grows by 5% every year. What will the population be after 2 years?
8. 8.A town has 11900 people. The population grows by 15% every year. What will the population be after 1 year?
9. 9.Find the compound interest on ₹17500 at 4% per year for 2 years, compounded every year (in ₹).
10. 10.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹53600 at 25% per year for 2 years, compounded every year (in ₹).
12. 12.A town has 25300 people. The population grows by 25% every year. What will the population be after 1 year?
13. 13.What is the difference between the compound interest and the simple interest on ₹10000 at 5% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹5000 at 8% per year for 2 years (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹35400 at 20% per year for 2 years (in ₹)?
16. 16.A scooter is worth ₹13700. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
17. 17.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
18. 18.What amount will ₹34000 grow to in 3 years at 20% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
20. 20.A town has 17500 people. The population grows by 20% every year. What will the population be after 3 years?
21. 21.What is the difference between the compound interest and the simple interest on ₹33600 at 25% per year for 2 years (in ₹)?
22. 22.A town has 56000 people. The population grows by 10% every year. What will the population be after 3 years?
23. 23.What amount will ₹28800 grow to in 2 years at 25% per year compound interest (in ₹)?
24. 24.A scooter is worth ₹14000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
25. 25.Find the compound interest on ₹2800 at 5% per year for 2 years, compounded every year (in ₹).
26. 26.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
27. 27.A scooter is worth ₹3700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹4600 at 20% per year for 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹11200 at 5% per year for 2 years (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹25200 at 5% per year for 2 years (in ₹)?
31. 31.A town has 20800 people. The population grows by 5% every year. What will the population be after 2 years?
32. 32.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
33. 33.A scooter is worth ₹14000. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
34. 34.Find the compound interest on ₹38500 at 20% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹12100 at 5% per year for 1 year, compounded every year (in ₹).
36. 36.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
37. 37.Find the compound interest on ₹2500 at 4% per year for 2 years, compounded every year (in ₹).
38. 38.A scooter is worth ₹55000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
39. 39.A town has 30000 people. The population grows by 4% every year. What will the population be after 2 years?
40. 40.Find the compound interest on ₹29700 at 8% per year for 1 year, compounded every year (in ₹).

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets