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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 679 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹52400 at 5% per year for 2 years (in ₹)?
  2. 2.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  3. 3.A scooter is worth ₹43000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹10000 at 12% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹18300 at 4% per year for 1 year, compounded every year (in ₹).
  6. 6.Find the compound interest on ₹11200 at 25% per year for 3 years, compounded every year (in ₹).
  7. 7.A town has 18500 people. The population grows by 5% every year. What will the population be after 1 year?
  8. 8.What amount will ₹13100 grow to in 1 year at 5% per year compound interest (in ₹)?
  9. 9.A scooter is worth ₹9600. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  10. 10.A scooter is worth ₹59200. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  11. 11.A scooter is worth ₹21400. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  12. 12.What is the difference between the compound interest and the simple interest on ₹52400 at 15% per year for 2 years (in ₹)?
  13. 13.Find the compound interest on ₹14400 at 25% per year for 1 year, compounded every year (in ₹).
  14. 14.A town has 26900 people. The population grows by 12% every year. What will the population be after 1 year?
  15. 15.A town has 14100 people. The population grows by 15% every year. What will the population be after 1 year?
  16. 16.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
  17. 17.Find the compound interest on ₹27200 at 20% per year for 2 years, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹25000 at 12% per year for 2 years (in ₹)?
  19. 19.Find the compound interest on ₹53200 at 10% per year for 1 year, compounded every year (in ₹).
  20. 20.What is the difference between the compound interest and the simple interest on ₹47600 at 25% per year for 2 years (in ₹)?
  21. 21.What is the difference between the compound interest and the simple interest on ₹59200 at 5% per year for 2 years (in ₹)?
  22. 22.What amount will ₹32400 grow to in 1 year at 5% per year compound interest (in ₹)?
  23. 23.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  24. 24.Find the compound interest on ₹33200 at 5% per year for 2 years, compounded every year (in ₹).
  25. 25.What amount will ₹26300 grow to in 2 years at 10% per year compound interest (in ₹)?
  26. 26.What amount will ₹30000 grow to in 1 year at 20% per year compound interest (in ₹)?
  27. 27.Find the compound interest on ₹55800 at 5% per year for 1 year, compounded every year (in ₹).
  28. 28.Find the compound interest on ₹4200 at 10% per year for 1 year, compounded every year (in ₹).
  29. 29.What amount will ₹21500 grow to in 1 year at 4% per year compound interest (in ₹)?
  30. 30.What amount will ₹58400 grow to in 2 years at 20% per year compound interest (in ₹)?
  31. 31.A town has 6400 people. The population grows by 4% every year. What will the population be after 1 year?
  32. 32.What amount will ₹23100 grow to in 1 year at 25% per year compound interest (in ₹)?
  33. 33.What amount will ₹54400 grow to in 3 years at 25% per year compound interest (in ₹)?
  34. 34.A scooter is worth ₹12500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  35. 35.Find the compound interest on ₹14100 at 12% per year for 1 year, compounded every year (in ₹).
  36. 36.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
  37. 37.Find the compound interest on ₹8400 at 12% per year for 1 year, compounded every year (in ₹).
  38. 38.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
  39. 39.What is the difference between the compound interest and the simple interest on ₹18400 at 10% per year for 2 years (in ₹)?
  40. 40.Find the compound interest on ₹25100 at 10% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 131
  2. 6859
  3. 31347
  4. 144
  5. 732
  6. 10675
  7. 19425
  8. 13755
  9. 9216
  10. 56832
  11. 17334
  12. 1179
  13. 3600
  14. 30128
  15. 16215
  16. 224
  17. 11968
  18. 360
  19. 5320
  20. 2975
  21. 148
  22. 34020
  23. 2522
  24. 3403
  25. 31823
  26. 36000
  27. 2790
  28. 420
  29. 22360
  30. 84096
  31. 6656
  32. 28875
  33. 106250
  34. 9680
  35. 1692
  36. 216
  37. 1008
  38. 46305
  39. 184
  40. 2510

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