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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 684 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹7200 at 20% per year for 2 years (in ₹)?
  2. 2.Find the compound interest on ₹48200 at 15% per year for 1 year, compounded every year (in ₹).
  3. 3.What is the difference between the compound interest and the simple interest on ₹48800 at 25% per year for 2 years (in ₹)?
  4. 4.A town has 42700 people. The population grows by 8% every year. What will the population be after 1 year?
  5. 5.A scooter is worth ₹48100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  6. 6.Find the compound interest on ₹39000 at 20% per year for 2 years, compounded every year (in ₹).
  7. 7.What amount will ₹53500 grow to in 1 year at 5% per year compound interest (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹5200 at 25% per year for 2 years (in ₹)?
  9. 9.What is the difference between the compound interest and the simple interest on ₹2000 at 5% per year for 2 years (in ₹)?
  10. 10.Find the compound interest on ₹40800 at 12% per year for 1 year, compounded every year (in ₹).
  11. 11.A scooter is worth ₹7300. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  12. 12.Find the compound interest on ₹35000 at 4% per year for 2 years, compounded every year (in ₹).
  13. 13.A scooter is worth ₹11500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  14. 14.A town has 50300 people. The population grows by 10% every year. What will the population be after 1 year?
  15. 15.What is the difference between the compound interest and the simple interest on ₹12500 at 12% per year for 2 years (in ₹)?
  16. 16.A town has 6000 people. The population grows by 10% every year. What will the population be after 3 years?
  17. 17.What is the difference between the compound interest and the simple interest on ₹21400 at 20% per year for 2 years (in ₹)?
  18. 18.What amount will ₹15400 grow to in 1 year at 25% per year compound interest (in ₹)?
  19. 19.Find the compound interest on ₹45300 at 10% per year for 2 years, compounded every year (in ₹).
  20. 20.What amount will ₹6400 grow to in 2 years at 20% per year compound interest (in ₹)?
  21. 21.Find the compound interest on ₹14500 at 25% per year for 1 year, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹10800 at 25% per year for 2 years, compounded every year (in ₹).
  23. 23.A town has 46300 people. The population grows by 10% every year. What will the population be after 2 years?
  24. 24.What is the difference between the compound interest and the simple interest on ₹9400 at 20% per year for 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹38800 at 5% per year for 2 years (in ₹)?
  26. 26.A scooter is worth ₹3200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  27. 27.What is the difference between the compound interest and the simple interest on ₹56400 at 5% per year for 2 years (in ₹)?
  28. 28.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  29. 29.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
  30. 30.What amount will ₹34400 grow to in 2 years at 25% per year compound interest (in ₹)?
  31. 31.Find the compound interest on ₹19400 at 12% per year for 1 year, compounded every year (in ₹).
  32. 32.What amount will ₹6800 grow to in 2 years at 25% per year compound interest (in ₹)?
  33. 33.What is the difference between the compound interest and the simple interest on ₹16000 at 20% per year for 2 years (in ₹)?
  34. 34.What amount will ₹5000 grow to in 2 years at 8% per year compound interest (in ₹)?
  35. 35.A town has 55000 people. The population grows by 10% every year. What will the population be after 3 years?
  36. 36.What amount will ₹14500 grow to in 3 years at 20% per year compound interest (in ₹)?
  37. 37.A town has 52900 people. The population grows by 12% every year. What will the population be after 1 year?
  38. 38.A town has 24000 people. The population grows by 15% every year. What will the population be after 3 years?
  39. 39.What is the difference between the compound interest and the simple interest on ₹6000 at 25% per year for 2 years (in ₹)?
  40. 40.Find the compound interest on ₹56700 at 25% per year for 1 year, compounded every year (in ₹).

Answer key

  1. 288
  2. 7230
  3. 3050
  4. 46116
  5. 46176
  6. 17160
  7. 56175
  8. 325
  9. 5
  10. 4896
  11. 7008
  12. 2856
  13. 10925
  14. 55330
  15. 180
  16. 7986
  17. 856
  18. 19250
  19. 9513
  20. 9216
  21. 3625
  22. 6075
  23. 56023
  24. 376
  25. 97
  26. 2888
  27. 141
  28. 2522
  29. 29169
  30. 53750
  31. 2328
  32. 10625
  33. 640
  34. 5832
  35. 73205
  36. 25056
  37. 59248
  38. 36501
  39. 375
  40. 14175

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