Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A town has 14700 people. The population grows by 10% every year. What will the population be after 1 year?
- 2.What is the difference between the compound interest and the simple interest on ₹57800 at 10% per year for 2 years (in ₹)?
- 3.Find the compound interest on ₹48000 at 20% per year for 3 years, compounded every year (in ₹).
- 4.A scooter is worth ₹16100. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
- 6.A town has 42500 people. The population grows by 8% every year. What will the population be after 2 years?
- 7.A scooter is worth ₹36600. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 8.Find the compound interest on ₹60000 at 12% per year for 2 years, compounded every year (in ₹).
- 9.Find the compound interest on ₹46000 at 10% per year for 2 years, compounded every year (in ₹).
- 10.What amount will ₹38400 grow to in 1 year at 4% per year compound interest (in ₹)?
- 11.A town has 3800 people. The population grows by 25% every year. What will the population be after 1 year?
- 12.What is the difference between the compound interest and the simple interest on ₹23500 at 20% per year for 2 years (in ₹)?
- 13.What amount will ₹44000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 14.Find the compound interest on ₹26400 at 5% per year for 2 years, compounded every year (in ₹).
- 15.What is the difference between the compound interest and the simple interest on ₹36000 at 25% per year for 2 years (in ₹)?
- 16.What amount will ₹17500 grow to in 2 years at 8% per year compound interest (in ₹)?
- 17.A town has 55900 people. The population grows by 25% every year. What will the population be after 1 year?
- 18.What is the difference between the compound interest and the simple interest on ₹57200 at 25% per year for 2 years (in ₹)?
- 19.A scooter is worth ₹16000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 20.What is the difference between the compound interest and the simple interest on ₹26000 at 25% per year for 2 years (in ₹)?
- 21.Find the compound interest on ₹10100 at 25% per year for 1 year, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹53900 at 10% per year for 2 years (in ₹)?
- 24.A scooter is worth ₹4800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 25.What amount will ₹28000 grow to in 1 year at 5% per year compound interest (in ₹)?
- 26.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
- 27.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
- 28.What amount will ₹10000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 29.What amount will ₹23000 grow to in 1 year at 5% per year compound interest (in ₹)?
- 30.What amount will ₹47700 grow to in 1 year at 8% per year compound interest (in ₹)?
- 31.A scooter is worth ₹40000. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 32.A town has 12800 people. The population grows by 25% every year. What will the population be after 2 years?
- 33.What amount will ₹17300 grow to in 1 year at 15% per year compound interest (in ₹)?
- 34.What is the difference between the compound interest and the simple interest on ₹15600 at 5% per year for 2 years (in ₹)?
- 35.Find the compound interest on ₹27000 at 10% per year for 3 years, compounded every year (in ₹).
- 36.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
- 37.Find the compound interest on ₹22500 at 20% per year for 3 years, compounded every year (in ₹).
- 38.Find the compound interest on ₹13500 at 10% per year for 1 year, compounded every year (in ₹).
- 39.What amount will ₹54800 grow to in 2 years at 15% per year compound interest (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹7800 at 10% per year for 2 years (in ₹)?
Answer key
- 16170
- 578
- 34944
- 13041
- 72
- 49572
- 29280
- 15264
- 9660
- 39936
- 4750
- 940
- 58190
- 2706
- 2250
- 20412
- 69875
- 3575
- 13718
- 1625
- 2525
- 44
- 539
- 3468
- 29400
- 9826
- 128
- 11664
- 24150
- 51516
- 16875
- 20000
- 19895
- 39
- 8937
- 4
- 16380
- 1350
- 72473
- 78
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