Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹7600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 2.What amount will ₹42500 grow to in 1 year at 20% per year compound interest (in ₹)?
- 3.Find the compound interest on ₹28000 at 5% per year for 2 years, compounded every year (in ₹).
- 4.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
- 5.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 6.Find the compound interest on ₹52500 at 8% per year for 2 years, compounded every year (in ₹).
- 7.What amount will ₹10800 grow to in 2 years at 25% per year compound interest (in ₹)?
- 8.Find the compound interest on ₹21000 at 20% per year for 3 years, compounded every year (in ₹).
- 9.A scooter is worth ₹34000. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
- 10.A town has 33600 people. The population grows by 5% every year. What will the population be after 2 years?
- 11.What amount will ₹57500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 12.A town has 42500 people. The population grows by 12% every year. What will the population be after 2 years?
- 13.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
- 14.What amount will ₹45200 grow to in 1 year at 20% per year compound interest (in ₹)?
- 15.Find the compound interest on ₹52500 at 10% per year for 2 years, compounded every year (in ₹).
- 16.A scooter is worth ₹18100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 17.Find the compound interest on ₹20000 at 4% per year for 2 years, compounded every year (in ₹).
- 18.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 19.A town has 44200 people. The population grows by 20% every year. What will the population be after 2 years?
- 20.Find the compound interest on ₹4600 at 20% per year for 1 year, compounded every year (in ₹).
- 21.Find the compound interest on ₹50900 at 25% per year for 1 year, compounded every year (in ₹).
- 22.A scooter is worth ₹12500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
- 23.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 24.What amount will ₹13300 grow to in 1 year at 5% per year compound interest (in ₹)?
- 25.A town has 2000 people. The population grows by 15% every year. What will the population be after 2 years?
- 26.A town has 43400 people. The population grows by 12% every year. What will the population be after 1 year?
- 27.A town has 12500 people. The population grows by 5% every year. What will the population be after 1 year?
- 28.Find the compound interest on ₹48000 at 15% per year for 3 years, compounded every year (in ₹).
- 29.A town has 42000 people. The population grows by 20% every year. What will the population be after 3 years?
- 30.What is the difference between the compound interest and the simple interest on ₹56000 at 20% per year for 2 years (in ₹)?
- 31.A town has 3000 people. The population grows by 10% every year. What will the population be after 3 years?
- 32.What is the difference between the compound interest and the simple interest on ₹13800 at 10% per year for 2 years (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹21500 at 20% per year for 2 years (in ₹)?
- 34.Find the compound interest on ₹37200 at 20% per year for 1 year, compounded every year (in ₹).
- 35.A scooter is worth ₹10400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 36.Find the compound interest on ₹9400 at 5% per year for 1 year, compounded every year (in ₹).
- 37.What amount will ₹3000 grow to in 1 year at 4% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹15500 at 20% per year for 3 years, compounded every year (in ₹).
- 39.What is the difference between the compound interest and the simple interest on ₹41700 at 10% per year for 2 years (in ₹)?
- 40.Find the compound interest on ₹27200 at 5% per year for 2 years, compounded every year (in ₹).
Answer key
- 6859
- 51000
- 2870
- 6305
- 27783
- 8736
- 16875
- 15288
- 27540
- 37044
- 62192
- 53312
- 216
- 54240
- 11025
- 17376
- 1632
- 12167
- 63648
- 920
- 12725
- 11520
- 48668
- 13965
- 2645
- 48608
- 13125
- 25002
- 72576
- 2240
- 3993
- 138
- 860
- 7440
- 9386
- 470
- 3120
- 11284
- 417
- 2788
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