Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 70 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹51200 at 12% per year for 1 year, compounded every year (in ₹).
2. 2.A scooter is worth ₹12500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
3. 3.Find the compound interest on ₹30000 at 10% per year for 2 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹19600 at 5% per year for 2 years (in ₹)?
6. 6.A town has 26400 people. The population grows by 25% every year. What will the population be after 2 years?
7. 7.What amount will ₹53100 grow to in 1 year at 10% per year compound interest (in ₹)?
8. 8.A town has 45000 people. The population grows by 8% every year. What will the population be after 2 years?
9. 9.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
10. 10.What amount will ₹14800 grow to in 1 year at 8% per year compound interest (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹47100 at 20% per year for 2 years (in ₹)?
12. 12.What amount will ₹27700 grow to in 1 year at 20% per year compound interest (in ₹)?
13. 13.A town has 25700 people. The population grows by 10% every year. What will the population be after 1 year?
14. 14.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
15. 15.What amount will ₹11700 grow to in 1 year at 12% per year compound interest (in ₹)?
16. 16.A town has 18900 people. The population grows by 5% every year. What will the population be after 1 year?
17. 17.Find the compound interest on ₹16500 at 20% per year for 2 years, compounded every year (in ₹).
18. 18.What amount will ₹30200 grow to in 1 year at 5% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹10400 at 10% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹56300 at 4% per year for 1 year, compounded every year (in ₹).
21. 21.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
22. 22.Find the compound interest on ₹14700 at 10% per year for 2 years, compounded every year (in ₹).
23. 23.A scooter is worth ₹13400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
24. 24.What amount will ₹25800 grow to in 1 year at 15% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹22500 at 8% per year for 2 years, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹57600 at 5% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹12800 at 10% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹11600 at 25% per year for 2 years, compounded every year (in ₹).
30. 30.What amount will ₹15000 grow to in 2 years at 8% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹40000 at 15% per year for 2 years (in ₹)?
33. 33.What amount will ₹47000 grow to in 1 year at 5% per year compound interest (in ₹)?
34. 34.What amount will ₹21200 grow to in 1 year at 10% per year compound interest (in ₹)?
35. 35.What is the difference between the compound interest and the simple interest on ₹11200 at 10% per year for 2 years (in ₹)?
36. 36.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
37. 37.What amount will ₹50800 grow to in 1 year at 15% per year compound interest (in ₹)?
38. 38.A scooter is worth ₹9000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
39. 39.A town has 35800 people. The population grows by 15% every year. What will the population be after 1 year?
40. 40.A town has 25400 people. The population grows by 10% every year. What will the population be after 2 years?

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