Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 701 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹20800 at 20% per year for 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹60000 at 4% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹14800 at 20% per year for 2 years, compounded every year (in ₹).
5. 5.What amount will ₹29500 grow to in 2 years at 10% per year compound interest (in ₹)?
6. 6.What amount will ₹17200 grow to in 1 year at 25% per year compound interest (in ₹)?
7. 7.A scooter is worth ₹25600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
8. 8.A town has 39200 people. The population grows by 5% every year. What will the population be after 2 years?
9. 9.What amount will ₹2600 grow to in 2 years at 20% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹7500 at 4% per year for 2 years, compounded every year (in ₹).
11. 11.What amount will ₹22500 grow to in 2 years at 12% per year compound interest (in ₹)?
12. 12.Find the compound interest on ₹6400 at 25% per year for 3 years, compounded every year (in ₹).
13. 13.A town has 6900 people. The population grows by 10% every year. What will the population be after 2 years?
14. 14.A scooter is worth ₹54500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
15. 15.A town has 8000 people. The population grows by 10% every year. What will the population be after 3 years?
16. 16.A scooter is worth ₹31300. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
17. 17.Find the compound interest on ₹48300 at 5% per year for 1 year, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹58100 at 20% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹10800 at 25% per year for 2 years (in ₹)?
20. 20.What amount will ₹40000 grow to in 2 years at 12% per year compound interest (in ₹)?
21. 21.A town has 44800 people. The population grows by 25% every year. What will the population be after 3 years?
22. 22.What amount will ₹38100 grow to in 1 year at 4% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹26900 at 25% per year for 1 year, compounded every year (in ₹).
24. 24.Find the compound interest on ₹43400 at 5% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹49800 at 20% per year for 2 years, compounded every year (in ₹).
26. 26.A scooter is worth ₹22500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
27. 27.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
28. 28.What is the difference between the compound interest and the simple interest on ₹38800 at 5% per year for 2 years (in ₹)?
29. 29.A scooter is worth ₹33500. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
30. 30.A scooter is worth ₹29800. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
31. 31.What amount will ₹46800 grow to in 1 year at 8% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
33. 33.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
34. 34.What is the difference between the compound interest and the simple interest on ₹14900 at 20% per year for 2 years (in ₹)?
35. 35.Find the compound interest on ₹49000 at 25% per year for 1 year, compounded every year (in ₹).
36. 36.A scooter is worth ₹45600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
37. 37.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
38. 38.A scooter is worth ₹37500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
39. 39.What is the difference between the compound interest and the simple interest on ₹57100 at 10% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹24700 at 20% per year for 1 year, compounded every year (in ₹).

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