Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹26300 at 20% per year for 2 years (in ₹)?
- 2.What amount will ₹53500 grow to in 1 year at 8% per year compound interest (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹21700 at 20% per year for 2 years (in ₹)?
- 4.What is the difference between the compound interest and the simple interest on ₹19000 at 10% per year for 2 years (in ₹)?
- 5.A scooter is worth ₹34400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 6.A town has 7000 people. The population grows by 25% every year. What will the population be after 1 year?
- 7.What is the difference between the compound interest and the simple interest on ₹53200 at 15% per year for 2 years (in ₹)?
- 8.What amount will ₹50800 grow to in 2 years at 25% per year compound interest (in ₹)?
- 9.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 10.What amount will ₹22300 grow to in 1 year at 20% per year compound interest (in ₹)?
- 11.Find the compound interest on ₹25200 at 15% per year for 2 years, compounded every year (in ₹).
- 12.Find the compound interest on ₹42400 at 10% per year for 2 years, compounded every year (in ₹).
- 13.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹55600 at 15% per year for 2 years (in ₹)?
- 15.Find the compound interest on ₹49000 at 10% per year for 3 years, compounded every year (in ₹).
- 16.Find the compound interest on ₹42800 at 15% per year for 1 year, compounded every year (in ₹).
- 17.What is the difference between the compound interest and the simple interest on ₹37500 at 8% per year for 2 years (in ₹)?
- 18.What amount will ₹18600 grow to in 1 year at 4% per year compound interest (in ₹)?
- 19.A town has 34300 people. The population grows by 10% every year. What will the population be after 1 year?
- 20.What amount will ₹47400 grow to in 1 year at 8% per year compound interest (in ₹)?
- 21.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹18000 at 10% per year for 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹27900 at 20% per year for 2 years (in ₹)?
- 24.A town has 9200 people. The population grows by 15% every year. What will the population be after 2 years?
- 25.What is the difference between the compound interest and the simple interest on ₹10300 at 20% per year for 2 years (in ₹)?
- 26.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
- 27.A town has 47600 people. The population grows by 10% every year. What will the population be after 2 years?
- 28.Find the compound interest on ₹29500 at 10% per year for 1 year, compounded every year (in ₹).
- 29.A scooter is worth ₹30000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 30.A scooter is worth ₹16500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 31.Find the compound interest on ₹15400 at 12% per year for 1 year, compounded every year (in ₹).
- 32.A town has 48000 people. The population grows by 5% every year. What will the population be after 1 year?
- 33.Find the compound interest on ₹35600 at 5% per year for 2 years, compounded every year (in ₹).
- 34.Find the compound interest on ₹23100 at 15% per year for 1 year, compounded every year (in ₹).
- 35.Find the compound interest on ₹11400 at 25% per year for 1 year, compounded every year (in ₹).
- 36.Find the compound interest on ₹25000 at 12% per year for 2 years, compounded every year (in ₹).
- 37.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
- 38.What is the difference between the compound interest and the simple interest on ₹21000 at 20% per year for 2 years (in ₹)?
- 39.What amount will ₹48000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 40.Find the compound interest on ₹20700 at 5% per year for 1 year, compounded every year (in ₹).
Answer key
- 1052
- 57780
- 868
- 190
- 31046
- 8750
- 1197
- 79375
- 18522
- 26760
- 8127
- 8904
- 540
- 1251
- 16219
- 6420
- 240
- 19344
- 37730
- 51192
- 1261
- 180
- 1116
- 12167
- 412
- 1664
- 57596
- 2950
- 15360
- 8448
- 1848
- 50400
- 3649
- 3465
- 2850
- 6360
- 2522
- 840
- 73002
- 1035
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