Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 2.A town has 35000 people. The population grows by 8% every year. What will the population be after 2 years?
- 3.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 4.A town has 6800 people. The population grows by 25% every year. What will the population be after 2 years?
- 5.What is the difference between the compound interest and the simple interest on ₹36900 at 20% per year for 2 years (in ₹)?
- 6.What amount will ₹9300 grow to in 1 year at 5% per year compound interest (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹7500 at 4% per year for 2 years (in ₹)?
- 8.What amount will ₹40000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 9.Find the compound interest on ₹48000 at 25% per year for 3 years, compounded every year (in ₹).
- 10.What is the difference between the compound interest and the simple interest on ₹14800 at 5% per year for 2 years (in ₹)?
- 11.A town has 23600 people. The population grows by 5% every year. What will the population be after 2 years?
- 12.What amount will ₹55000 grow to in 1 year at 10% per year compound interest (in ₹)?
- 13.What is the difference between the compound interest and the simple interest on ₹37500 at 12% per year for 2 years (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹6000 at 5% per year for 2 years (in ₹)?
- 15.What amount will ₹42600 grow to in 1 year at 12% per year compound interest (in ₹)?
- 16.What is the difference between the compound interest and the simple interest on ₹56000 at 25% per year for 2 years (in ₹)?
- 17.What amount will ₹53600 grow to in 1 year at 4% per year compound interest (in ₹)?
- 18.A scooter is worth ₹25500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 19.Find the compound interest on ₹13000 at 20% per year for 1 year, compounded every year (in ₹).
- 20.A town has 11300 people. The population grows by 5% every year. What will the population be after 1 year?
- 21.What is the difference between the compound interest and the simple interest on ₹13600 at 25% per year for 2 years (in ₹)?
- 22.What amount will ₹45800 grow to in 1 year at 10% per year compound interest (in ₹)?
- 23.What amount will ₹25600 grow to in 3 years at 25% per year compound interest (in ₹)?
- 24.A scooter is worth ₹27500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 25.A town has 2400 people. The population grows by 20% every year. What will the population be after 2 years?
- 26.Find the compound interest on ₹42400 at 20% per year for 2 years, compounded every year (in ₹).
- 27.A scooter is worth ₹11600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 28.Find the compound interest on ₹5000 at 10% per year for 3 years, compounded every year (in ₹).
- 29.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
- 30.Find the compound interest on ₹46400 at 25% per year for 3 years, compounded every year (in ₹).
- 31.What amount will ₹52800 grow to in 2 years at 25% per year compound interest (in ₹)?
- 32.A town has 53200 people. The population grows by 20% every year. What will the population be after 2 years?
- 33.Find the compound interest on ₹3200 at 25% per year for 3 years, compounded every year (in ₹).
- 34.Find the compound interest on ₹43800 at 20% per year for 1 year, compounded every year (in ₹).
- 35.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
- 36.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 37.What amount will ₹18600 grow to in 1 year at 5% per year compound interest (in ₹)?
- 38.What amount will ₹24600 grow to in 1 year at 25% per year compound interest (in ₹)?
- 39.A town has 35300 people. The population grows by 10% every year. What will the population be after 1 year?
- 40.A town has 8900 people. The population grows by 5% every year. What will the population be after 1 year?
Answer key
- 1261
- 40824
- 12167
- 10625
- 1476
- 9765
- 12
- 46305
- 45750
- 37
- 26019
- 60500
- 540
- 15
- 47712
- 3500
- 55744
- 13056
- 2600
- 11865
- 850
- 50380
- 50000
- 23276
- 3456
- 18656
- 10469
- 1655
- 7566
- 44225
- 82500
- 76608
- 3050
- 8760
- 4167
- 5044
- 19530
- 30750
- 38830
- 9345
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