Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 710 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 34900 people. The population grows by 10% every year. What will the population be after 1 year?
2. 2.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹27500 at 4% per year for 2 years, compounded every year (in ₹).
4. 4.Find the compound interest on ₹11300 at 20% per year for 2 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹5300 at 4% per year for 1 year, compounded every year (in ₹).
6. 6.What amount will ₹4800 grow to in 2 years at 5% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
8. 8.What amount will ₹47000 grow to in 3 years at 10% per year compound interest (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹6400 at 25% per year for 2 years (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹35600 at 15% per year for 2 years (in ₹)?
11. 11.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
12. 12.What amount will ₹26000 grow to in 2 years at 20% per year compound interest (in ₹)?
13. 13.What amount will ₹57200 grow to in 2 years at 5% per year compound interest (in ₹)?
14. 14.What amount will ₹27500 grow to in 2 years at 8% per year compound interest (in ₹)?
15. 15.A scooter is worth ₹36800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹5000 at 4% per year for 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹57200 at 25% per year for 2 years (in ₹)?
18. 18.A town has 35300 people. The population grows by 10% every year. What will the population be after 2 years?
19. 19.A scooter is worth ₹27000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
20. 20.A town has 2800 people. The population grows by 25% every year. What will the population be after 2 years?
21. 21.Find the compound interest on ₹42500 at 8% per year for 2 years, compounded every year (in ₹).
22. 22.A scooter is worth ₹45700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
23. 23.A scooter is worth ₹24000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
24. 24.Find the compound interest on ₹33600 at 4% per year for 1 year, compounded every year (in ₹).
25. 25.Find the compound interest on ₹37500 at 12% per year for 2 years, compounded every year (in ₹).
26. 26.What amount will ₹24000 grow to in 3 years at 5% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹41600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
28. 28.Find the compound interest on ₹56200 at 15% per year for 1 year, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹55900 at 20% per year for 2 years, compounded every year (in ₹).
31. 31.Find the compound interest on ₹42700 at 25% per year for 1 year, compounded every year (in ₹).
32. 32.What amount will ₹50000 grow to in 2 years at 12% per year compound interest (in ₹)?
33. 33.A town has 32600 people. The population grows by 10% every year. What will the population be after 2 years?
34. 34.What is the difference between the compound interest and the simple interest on ₹12500 at 8% per year for 2 years (in ₹)?
35. 35.A town has 52000 people. The population grows by 25% every year. What will the population be after 2 years?
36. 36.Find the compound interest on ₹18200 at 12% per year for 1 year, compounded every year (in ₹).
37. 37.What amount will ₹34500 grow to in 3 years at 20% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹32500 at 8% per year for 2 years, compounded every year (in ₹).
39. 39.A scooter is worth ₹25300. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
40. 40.Find the compound interest on ₹55200 at 10% per year for 2 years, compounded every year (in ₹).

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