← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 713 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What amount will ₹45000 grow to in 2 years at 8% per year compound interest (in ₹)?
  2. 2.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
  3. 3.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
  4. 4.What is the difference between the compound interest and the simple interest on ₹19100 at 20% per year for 2 years (in ₹)?
  5. 5.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
  6. 6.What is the difference between the compound interest and the simple interest on ₹44000 at 25% per year for 2 years (in ₹)?
  7. 7.What amount will ₹41000 grow to in 3 years at 10% per year compound interest (in ₹)?
  8. 8.What amount will ₹57300 grow to in 1 year at 12% per year compound interest (in ₹)?
  9. 9.A town has 39500 people. The population grows by 25% every year. What will the population be after 1 year?
  10. 10.What is the difference between the compound interest and the simple interest on ₹2800 at 25% per year for 2 years (in ₹)?
  11. 11.A town has 47500 people. The population grows by 12% every year. What will the population be after 2 years?
  12. 12.What amount will ₹23300 grow to in 1 year at 5% per year compound interest (in ₹)?
  13. 13.What amount will ₹9400 grow to in 1 year at 12% per year compound interest (in ₹)?
  14. 14.What amount will ₹7500 grow to in 2 years at 8% per year compound interest (in ₹)?
  15. 15.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
  16. 16.What is the difference between the compound interest and the simple interest on ₹14800 at 15% per year for 2 years (in ₹)?
  17. 17.Find the compound interest on ₹26600 at 5% per year for 1 year, compounded every year (in ₹).
  18. 18.What amount will ₹33600 grow to in 2 years at 15% per year compound interest (in ₹)?
  19. 19.A town has 6000 people. The population grows by 25% every year. What will the population be after 2 years?
  20. 20.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
  21. 21.Find the compound interest on ₹33600 at 10% per year for 1 year, compounded every year (in ₹).
  22. 22.What amount will ₹2500 grow to in 2 years at 8% per year compound interest (in ₹)?
  23. 23.A scooter is worth ₹45200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
  24. 24.A town has 29400 people. The population grows by 25% every year. What will the population be after 1 year?
  25. 25.A town has 4800 people. The population grows by 25% every year. What will the population be after 3 years?
  26. 26.What is the difference between the compound interest and the simple interest on ₹42000 at 5% per year for 2 years (in ₹)?
  27. 27.A town has 16200 people. The population grows by 8% every year. What will the population be after 1 year?
  28. 28.A scooter is worth ₹20000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  29. 29.What amount will ₹24200 grow to in 1 year at 20% per year compound interest (in ₹)?
  30. 30.What amount will ₹31000 grow to in 3 years at 20% per year compound interest (in ₹)?
  31. 31.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
  32. 32.Find the compound interest on ₹46000 at 10% per year for 3 years, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹52300 at 15% per year for 1 year, compounded every year (in ₹).
  34. 34.What amount will ₹60000 grow to in 3 years at 10% per year compound interest (in ₹)?
  35. 35.A town has 23200 people. The population grows by 25% every year. What will the population be after 1 year?
  36. 36.What amount will ₹8000 grow to in 1 year at 4% per year compound interest (in ₹)?
  37. 37.What is the difference between the compound interest and the simple interest on ₹20000 at 8% per year for 2 years (in ₹)?
  38. 38.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
  39. 39.What is the difference between the compound interest and the simple interest on ₹53200 at 25% per year for 2 years (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹20400 at 25% per year for 2 years (in ₹)?

Answer key

  1. 52488
  2. 27783
  3. 43740
  4. 764
  5. 29169
  6. 2750
  7. 54571
  8. 64176
  9. 49375
  10. 175
  11. 59584
  12. 24465
  13. 10528
  14. 8748
  15. 8827
  16. 333
  17. 1330
  18. 44436
  19. 9375
  20. 4167
  21. 3360
  22. 2916
  23. 25425
  24. 36750
  25. 9375
  26. 105
  27. 17496
  28. 10240
  29. 29040
  30. 53568
  31. 36
  32. 15226
  33. 7845
  34. 79860
  35. 29000
  36. 8320
  37. 128
  38. 20835
  39. 3325
  40. 1275

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets