← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 719 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.Find the compound interest on ₹44000 at 12% per year for 1 year, compounded every year (in ₹).
  2. 2.What amount will ₹27500 grow to in 2 years at 20% per year compound interest (in ₹)?
  3. 3.What amount will ₹32800 grow to in 2 years at 5% per year compound interest (in ₹)?
  4. 4.Find the compound interest on ₹3500 at 20% per year for 2 years, compounded every year (in ₹).
  5. 5.What is the difference between the compound interest and the simple interest on ₹38500 at 20% per year for 2 years (in ₹)?
  6. 6.Find the compound interest on ₹7400 at 20% per year for 1 year, compounded every year (in ₹).
  7. 7.A town has 58000 people. The population grows by 20% every year. What will the population be after 3 years?
  8. 8.Find the compound interest on ₹47500 at 8% per year for 2 years, compounded every year (in ₹).
  9. 9.What amount will ₹37500 grow to in 2 years at 12% per year compound interest (in ₹)?
  10. 10.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
  11. 11.What is the difference between the compound interest and the simple interest on ₹22500 at 12% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹31900 at 15% per year for 1 year, compounded every year (in ₹).
  14. 14.Find the compound interest on ₹44000 at 5% per year for 2 years, compounded every year (in ₹).
  15. 15.What amount will ₹10000 grow to in 3 years at 20% per year compound interest (in ₹)?
  16. 16.Find the compound interest on ₹28100 at 4% per year for 1 year, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹29300 at 15% per year for 1 year, compounded every year (in ₹).
  18. 18.What is the difference between the compound interest and the simple interest on ₹37000 at 20% per year for 2 years (in ₹)?
  19. 19.What amount will ₹13200 grow to in 2 years at 5% per year compound interest (in ₹)?
  20. 20.A scooter is worth ₹23500. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  21. 21.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹50400 at 10% per year for 1 year, compounded every year (in ₹).
  23. 23.What amount will ₹10000 grow to in 2 years at 20% per year compound interest (in ₹)?
  24. 24.What amount will ₹13000 grow to in 3 years at 10% per year compound interest (in ₹)?
  25. 25.Find the compound interest on ₹13400 at 20% per year for 1 year, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
  27. 27.A town has 2500 people. The population grows by 8% every year. What will the population be after 2 years?
  28. 28.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹17200 at 25% per year for 2 years (in ₹)?
  30. 30.A town has 37000 people. The population grows by 20% every year. What will the population be after 3 years?
  31. 31.What is the difference between the compound interest and the simple interest on ₹13200 at 25% per year for 2 years (in ₹)?
  32. 32.A town has 39400 people. The population grows by 10% every year. What will the population be after 1 year?
  33. 33.A town has 33300 people. The population grows by 20% every year. What will the population be after 2 years?
  34. 34.Find the compound interest on ₹41400 at 4% per year for 1 year, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹19000 at 10% per year for 3 years, compounded every year (in ₹).
  36. 36.Find the compound interest on ₹50500 at 15% per year for 1 year, compounded every year (in ₹).
  37. 37.What is the difference between the compound interest and the simple interest on ₹8000 at 25% per year for 2 years (in ₹)?
  38. 38.What amount will ₹47500 grow to in 3 years at 20% per year compound interest (in ₹)?
  39. 39.What amount will ₹51300 grow to in 1 year at 15% per year compound interest (in ₹)?
  40. 40.A scooter is worth ₹16800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?

Answer key

  1. 5280
  2. 39600
  3. 36162
  4. 1540
  5. 1540
  6. 1480
  7. 100224
  8. 7904
  9. 47040
  10. 9261
  11. 324
  12. 1664
  13. 4785
  14. 4510
  15. 17280
  16. 1124
  17. 4395
  18. 1480
  19. 14553
  20. 22560
  21. 20835
  22. 5040
  23. 14400
  24. 17303
  25. 2680
  26. 612
  27. 2916
  28. 216
  29. 1075
  30. 63936
  31. 825
  32. 43340
  33. 47952
  34. 1656
  35. 6289
  36. 7575
  37. 500
  38. 82080
  39. 58995
  40. 9450

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets