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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 722 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 16000 people. The population grows by 15% every year. What will the population be after 3 years?
  2. 2.A town has 15700 people. The population grows by 4% every year. What will the population be after 1 year?
  3. 3.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
  4. 4.Find the compound interest on ₹30000 at 5% per year for 2 years, compounded every year (in ₹).
  5. 5.What is the difference between the compound interest and the simple interest on ₹35100 at 20% per year for 2 years (in ₹)?
  6. 6.What amount will ₹35200 grow to in 1 year at 12% per year compound interest (in ₹)?
  7. 7.What is the difference between the compound interest and the simple interest on ₹40800 at 20% per year for 2 years (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹10800 at 25% per year for 2 years (in ₹)?
  9. 9.A town has 55000 people. The population grows by 4% every year. What will the population be after 2 years?
  10. 10.Find the compound interest on ₹54900 at 12% per year for 1 year, compounded every year (in ₹).
  11. 11.What amount will ₹16400 grow to in 2 years at 25% per year compound interest (in ₹)?
  12. 12.What amount will ₹17300 grow to in 1 year at 10% per year compound interest (in ₹)?
  13. 13.What amount will ₹49800 grow to in 1 year at 5% per year compound interest (in ₹)?
  14. 14.Find the compound interest on ₹4500 at 10% per year for 1 year, compounded every year (in ₹).
  15. 15.A scooter is worth ₹32000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
  16. 16.What is the difference between the compound interest and the simple interest on ₹4800 at 25% per year for 2 years (in ₹)?
  17. 17.A scooter is worth ₹38600. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  18. 18.A town has 5000 people. The population grows by 4% every year. What will the population be after 2 years?
  19. 19.Find the compound interest on ₹12500 at 8% per year for 2 years, compounded every year (in ₹).
  20. 20.A town has 16000 people. The population grows by 5% every year. What will the population be after 3 years?
  21. 21.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹42500 at 12% per year for 2 years, compounded every year (in ₹).
  23. 23.What amount will ₹36700 grow to in 1 year at 12% per year compound interest (in ₹)?
  24. 24.A scooter is worth ₹41600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹55000 at 12% per year for 2 years (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹24000 at 15% per year for 2 years (in ₹)?
  27. 27.A scooter is worth ₹40000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
  28. 28.A scooter is worth ₹8700. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  29. 29.What amount will ₹50200 grow to in 1 year at 4% per year compound interest (in ₹)?
  30. 30.What amount will ₹52800 grow to in 1 year at 10% per year compound interest (in ₹)?
  31. 31.What amount will ₹5700 grow to in 1 year at 25% per year compound interest (in ₹)?
  32. 32.Find the compound interest on ₹18500 at 20% per year for 3 years, compounded every year (in ₹).
  33. 33.A scooter is worth ₹28800. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
  34. 34.A town has 21300 people. The population grows by 4% every year. What will the population be after 1 year?
  35. 35.Find the compound interest on ₹19700 at 5% per year for 1 year, compounded every year (in ₹).
  36. 36.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
  37. 37.Find the compound interest on ₹47000 at 8% per year for 1 year, compounded every year (in ₹).
  38. 38.What amount will ₹54700 grow to in 1 year at 15% per year compound interest (in ₹)?
  39. 39.A scooter is worth ₹10200. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹27600 at 5% per year for 2 years (in ₹)?

Answer key

  1. 24334
  2. 16328
  3. 252
  4. 3075
  5. 1404
  6. 39424
  7. 1632
  8. 675
  9. 59488
  10. 6588
  11. 25625
  12. 19030
  13. 52290
  14. 450
  15. 19652
  16. 300
  17. 34740
  18. 5408
  19. 2080
  20. 18522
  21. 9152
  22. 10812
  23. 41104
  24. 37544
  25. 792
  26. 540
  27. 20480
  28. 8265
  29. 52208
  30. 58080
  31. 7125
  32. 13468
  33. 12150
  34. 22152
  35. 985
  36. 504
  37. 3760
  38. 62905
  39. 8976
  40. 69

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