Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 728 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹18800. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹32500 at 12% per year for 2 years (in ₹)?
3. 3.Find the compound interest on ₹6000 at 25% per year for 2 years, compounded every year (in ₹).
4. 4.What amount will ₹37700 grow to in 1 year at 20% per year compound interest (in ₹)?
5. 5.What amount will ₹13300 grow to in 1 year at 10% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹30800 at 5% per year for 2 years (in ₹)?
7. 7.A town has 27500 people. The population grows by 4% every year. What will the population be after 2 years?
8. 8.Find the compound interest on ₹10000 at 8% per year for 2 years, compounded every year (in ₹).
9. 9.What amount will ₹32100 grow to in 2 years at 10% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹44400 at 5% per year for 2 years (in ₹)?
11. 11.A scooter is worth ₹8400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
12. 12.Find the compound interest on ₹15000 at 10% per year for 3 years, compounded every year (in ₹).
13. 13.What amount will ₹22600 grow to in 1 year at 4% per year compound interest (in ₹)?
14. 14.Find the compound interest on ₹33600 at 4% per year for 1 year, compounded every year (in ₹).
15. 15.Find the compound interest on ₹23600 at 20% per year for 1 year, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹10300 at 20% per year for 2 years, compounded every year (in ₹).
18. 18.A town has 16100 people. The population grows by 10% every year. What will the population be after 2 years?
19. 19.Find the compound interest on ₹41200 at 15% per year for 2 years, compounded every year (in ₹).
20. 20.A town has 13600 people. The population grows by 5% every year. What will the population be after 2 years?
21. 21.A scooter is worth ₹35400. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
22. 22.Find the compound interest on ₹32000 at 15% per year for 3 years, compounded every year (in ₹).
23. 23.A town has 53700 people. The population grows by 10% every year. What will the population be after 1 year?
24. 24.What amount will ₹27000 grow to in 3 years at 10% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹21600 at 25% per year for 1 year, compounded every year (in ₹).
26. 26.What amount will ₹31200 grow to in 2 years at 10% per year compound interest (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹16200 at 10% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
29. 29.What is the difference between the compound interest and the simple interest on ₹50000 at 5% per year for 2 years (in ₹)?
30. 30.A scooter is worth ₹27500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
31. 31.Find the compound interest on ₹60000 at 10% per year for 3 years, compounded every year (in ₹).
32. 32.What amount will ₹27300 grow to in 2 years at 10% per year compound interest (in ₹)?
33. 33.A town has 15400 people. The population grows by 25% every year. What will the population be after 1 year?
34. 34.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
35. 35.A scooter is worth ₹56000. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
36. 36.Find the compound interest on ₹14400 at 25% per year for 3 years, compounded every year (in ₹).
37. 37.What amount will ₹30000 grow to in 2 years at 4% per year compound interest (in ₹)?
38. 38.Find the compound interest on ₹38000 at 5% per year for 2 years, compounded every year (in ₹).
39. 39.What amount will ₹12500 grow to in 2 years at 8% per year compound interest (in ₹)?
40. 40.What amount will ₹41000 grow to in 3 years at 10% per year compound interest (in ₹)?

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