Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 731 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A town has 56700 people. The population grows by 20% every year. What will the population be after 2 years?
2. 2.A scooter is worth ₹9700. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
3. 3.Find the compound interest on ₹56400 at 15% per year for 2 years, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹44000 at 25% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹48300 at 10% per year for 2 years (in ₹)?
6. 6.A town has 3500 people. The population grows by 10% every year. What will the population be after 2 years?
7. 7.Find the compound interest on ₹27100 at 10% per year for 2 years, compounded every year (in ₹).
8. 8.A town has 54900 people. The population grows by 12% every year. What will the population be after 1 year?
9. 9.What amount will ₹17500 grow to in 2 years at 4% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹51000 at 12% per year for 1 year, compounded every year (in ₹).
12. 12.What is the difference between the compound interest and the simple interest on ₹17500 at 12% per year for 2 years (in ₹)?
13. 13.A town has 29600 people. The population grows by 25% every year. What will the population be after 2 years?
14. 14.Find the compound interest on ₹19200 at 20% per year for 1 year, compounded every year (in ₹).
15. 15.Find the compound interest on ₹25500 at 20% per year for 3 years, compounded every year (in ₹).
16. 16.A town has 53300 people. The population grows by 8% every year. What will the population be after 1 year?
17. 17.A town has 32900 people. The population grows by 25% every year. What will the population be after 1 year?
18. 18.What amount will ₹35900 grow to in 1 year at 25% per year compound interest (in ₹)?
19. 19.Find the compound interest on ₹42800 at 12% per year for 1 year, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹57200 at 25% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹41600 at 15% per year for 2 years (in ₹)?
22. 22.Find the compound interest on ₹53800 at 15% per year for 1 year, compounded every year (in ₹).
23. 23.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
24. 24.Find the compound interest on ₹49700 at 10% per year for 2 years, compounded every year (in ₹).
25. 25.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
26. 26.What amount will ₹27200 grow to in 2 years at 15% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
28. 28.Find the compound interest on ₹22400 at 10% per year for 1 year, compounded every year (in ₹).
29. 29.A scooter is worth ₹54700. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
30. 30.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
31. 31.Find the compound interest on ₹23100 at 5% per year for 1 year, compounded every year (in ₹).
32. 32.Find the compound interest on ₹46800 at 10% per year for 2 years, compounded every year (in ₹).
33. 33.A town has 19900 people. The population grows by 10% every year. What will the population be after 2 years?
34. 34.What amount will ₹46400 grow to in 3 years at 25% per year compound interest (in ₹)?
35. 35.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
36. 36.A town has 38700 people. The population grows by 10% every year. What will the population be after 1 year?
37. 37.Find the compound interest on ₹52500 at 12% per year for 2 years, compounded every year (in ₹).
38. 38.What amount will ₹52500 grow to in 2 years at 8% per year compound interest (in ₹)?
39. 39.What amount will ₹15000 grow to in 2 years at 12% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹13000 at 8% per year for 1 year, compounded every year (in ₹).

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