Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 734 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹23200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
2. 2.A scooter is worth ₹16200. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
3. 3.Find the compound interest on ₹13400 at 10% per year for 1 year, compounded every year (in ₹).
4. 4.Find the compound interest on ₹32500 at 4% per year for 2 years, compounded every year (in ₹).
5. 5.What is the difference between the compound interest and the simple interest on ₹58400 at 5% per year for 2 years (in ₹)?
6. 6.What amount will ₹13400 grow to in 1 year at 15% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹6200 at 20% per year for 2 years (in ₹)?
8. 8.What is the difference between the compound interest and the simple interest on ₹12000 at 15% per year for 2 years (in ₹)?
9. 9.Find the compound interest on ₹28800 at 25% per year for 3 years, compounded every year (in ₹).
10. 10.A town has 34500 people. The population grows by 20% every year. What will the population be after 1 year?
11. 11.What is the difference between the compound interest and the simple interest on ₹42800 at 5% per year for 2 years (in ₹)?
12. 12.A scooter is worth ₹30000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
13. 13.A town has 12600 people. The population grows by 8% every year. What will the population be after 1 year?
14. 14.What amount will ₹5100 grow to in 1 year at 8% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹13900 at 20% per year for 2 years (in ₹)?
16. 16.A town has 31100 people. The population grows by 20% every year. What will the population be after 1 year?
17. 17.What amount will ₹25000 grow to in 3 years at 10% per year compound interest (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹42400 at 25% per year for 2 years (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹29400 at 10% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
21. 21.What amount will ₹41300 grow to in 1 year at 12% per year compound interest (in ₹)?
22. 22.A town has 24900 people. The population grows by 15% every year. What will the population be after 1 year?
23. 23.Find the compound interest on ₹24000 at 20% per year for 3 years, compounded every year (in ₹).
24. 24.A scooter is worth ₹6400. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
25. 25.What amount will ₹32000 grow to in 3 years at 25% per year compound interest (in ₹)?
26. 26.A town has 8000 people. The population grows by 15% every year. What will the population be after 3 years?
27. 27.A town has 19400 people. The population grows by 4% every year. What will the population be after 1 year?
28. 28.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
31. 31.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
32. 32.Find the compound interest on ₹48400 at 20% per year for 2 years, compounded every year (in ₹).
33. 33.Find the compound interest on ₹55000 at 5% per year for 1 year, compounded every year (in ₹).
34. 34.What amount will ₹22300 grow to in 1 year at 25% per year compound interest (in ₹)?
35. 35.A town has 10000 people. The population grows by 12% every year. What will the population be after 2 years?
36. 36.Find the compound interest on ₹51000 at 10% per year for 3 years, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
38. 38.Find the compound interest on ₹40000 at 20% per year for 3 years, compounded every year (in ₹).
39. 39.What amount will ₹28000 grow to in 1 year at 15% per year compound interest (in ₹)?
40. 40.What amount will ₹24000 grow to in 3 years at 20% per year compound interest (in ₹)?

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