Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
- 2.A scooter is worth ₹4800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 3.Find the compound interest on ₹32500 at 4% per year for 2 years, compounded every year (in ₹).
- 4.Find the compound interest on ₹22400 at 25% per year for 2 years, compounded every year (in ₹).
- 5.A town has 8000 people. The population grows by 5% every year. What will the population be after 2 years?
- 6.A scooter is worth ₹18200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 7.What is the difference between the compound interest and the simple interest on ₹54000 at 15% per year for 2 years (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹3600 at 25% per year for 2 years (in ₹)?
- 9.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
- 10.Find the compound interest on ₹60000 at 12% per year for 2 years, compounded every year (in ₹).
- 11.A town has 19200 people. The population grows by 25% every year. What will the population be after 3 years?
- 12.Find the compound interest on ₹7000 at 10% per year for 3 years, compounded every year (in ₹).
- 13.What amount will ₹19800 grow to in 1 year at 12% per year compound interest (in ₹)?
- 14.What is the difference between the compound interest and the simple interest on ₹45600 at 25% per year for 2 years (in ₹)?
- 15.Find the compound interest on ₹59100 at 5% per year for 1 year, compounded every year (in ₹).
- 16.What is the difference between the compound interest and the simple interest on ₹52400 at 5% per year for 2 years (in ₹)?
- 17.What amount will ₹50000 grow to in 1 year at 10% per year compound interest (in ₹)?
- 18.Find the compound interest on ₹57500 at 20% per year for 3 years, compounded every year (in ₹).
- 19.What is the difference between the compound interest and the simple interest on ₹24400 at 15% per year for 2 years (in ₹)?
- 20.A scooter is worth ₹5700. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
- 21.What is the difference between the compound interest and the simple interest on ₹24800 at 15% per year for 2 years (in ₹)?
- 22.Find the compound interest on ₹9900 at 8% per year for 1 year, compounded every year (in ₹).
- 23.What is the difference between the compound interest and the simple interest on ₹44000 at 5% per year for 2 years (in ₹)?
- 24.A town has 30400 people. The population grows by 25% every year. What will the population be after 3 years?
- 25.A scooter is worth ₹22100. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
- 26.A town has 37000 people. The population grows by 10% every year. What will the population be after 3 years?
- 27.What amount will ₹5700 grow to in 1 year at 8% per year compound interest (in ₹)?
- 28.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
- 29.Find the compound interest on ₹56400 at 15% per year for 1 year, compounded every year (in ₹).
- 30.Find the compound interest on ₹27300 at 15% per year for 1 year, compounded every year (in ₹).
- 31.What amount will ₹23800 grow to in 2 years at 10% per year compound interest (in ₹)?
- 32.What amount will ₹6500 grow to in 2 years at 10% per year compound interest (in ₹)?
- 33.A town has 23700 people. The population grows by 10% every year. What will the population be after 1 year?
- 34.A scooter is worth ₹33600. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
- 35.What is the difference between the compound interest and the simple interest on ₹14100 at 10% per year for 2 years (in ₹)?
- 36.Find the compound interest on ₹55000 at 8% per year for 2 years, compounded every year (in ₹).
- 37.What is the difference between the compound interest and the simple interest on ₹6300 at 20% per year for 2 years (in ₹)?
- 38.Find the compound interest on ₹23300 at 15% per year for 1 year, compounded every year (in ₹).
- 39.A town has 43200 people. The population grows by 15% every year. What will the population be after 2 years?
- 40.What amount will ₹25700 grow to in 2 years at 10% per year compound interest (in ₹)?
Answer key
- 144
- 4332
- 2652
- 12600
- 8820
- 17290
- 1215
- 225
- 36
- 15264
- 37500
- 2317
- 22176
- 2850
- 2955
- 131
- 55000
- 41860
- 549
- 4275
- 558
- 792
- 110
- 59375
- 17680
- 49247
- 6156
- 21632
- 8460
- 4095
- 28798
- 7865
- 26070
- 14175
- 141
- 9152
- 252
- 3495
- 57132
- 31097
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