Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 745 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹5700 grow to in 1 year at 20% per year compound interest (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹57500 at 12% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹52500 at 8% per year for 2 years (in ₹)?
4. 4.A town has 12400 people. The population grows by 15% every year. What will the population be after 2 years?
5. 5.What amount will ₹3000 grow to in 2 years at 20% per year compound interest (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹18800 at 5% per year for 2 years (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹50000 at 8% per year for 2 years (in ₹)?
8. 8.What amount will ₹24200 grow to in 1 year at 5% per year compound interest (in ₹)?
9. 9.What amount will ₹18700 grow to in 1 year at 8% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹49200 at 15% per year for 2 years (in ₹)?
11. 11.A scooter is worth ₹24100. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹12400 at 25% per year for 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹52800 at 10% per year for 2 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹14800 at 5% per year for 2 years (in ₹)?
15. 15.A town has 16000 people. The population grows by 25% every year. What will the population be after 2 years?
16. 16.What amount will ₹45100 grow to in 1 year at 8% per year compound interest (in ₹)?
17. 17.Find the compound interest on ₹8000 at 15% per year for 2 years, compounded every year (in ₹).
18. 18.What is the difference between the compound interest and the simple interest on ₹29500 at 10% per year for 2 years (in ₹)?
19. 19.A scooter is worth ₹30200. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
20. 20.A scooter is worth ₹25700. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹27200 at 10% per year for 2 years (in ₹)?
22. 22.A town has 18800 people. The population grows by 25% every year. What will the population be after 1 year?
23. 23.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
24. 24.What amount will ₹36000 grow to in 3 years at 20% per year compound interest (in ₹)?
25. 25.Find the compound interest on ₹35000 at 8% per year for 2 years, compounded every year (in ₹).
26. 26.Find the compound interest on ₹16300 at 4% per year for 1 year, compounded every year (in ₹).
27. 27.A scooter is worth ₹32500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
28. 28.What amount will ₹50000 grow to in 3 years at 10% per year compound interest (in ₹)?
29. 29.Find the compound interest on ₹28800 at 25% per year for 3 years, compounded every year (in ₹).
30. 30.What amount will ₹10400 grow to in 1 year at 10% per year compound interest (in ₹)?
31. 31.What amount will ₹38400 grow to in 3 years at 25% per year compound interest (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹44800 at 5% per year for 2 years (in ₹)?
33. 33.A scooter is worth ₹6000. Its value falls by 8% every year. What will it be worth after 1 year (in ₹)?
34. 34.Find the compound interest on ₹49500 at 8% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹2100 at 10% per year for 2 years, compounded every year (in ₹).
36. 36.What amount will ₹25000 grow to in 3 years at 10% per year compound interest (in ₹)?
37. 37.What amount will ₹48000 grow to in 3 years at 5% per year compound interest (in ₹)?
38. 38.A scooter is worth ₹9000. Its value falls by 12% every year. What will it be worth after 1 year (in ₹)?
39. 39.Find the compound interest on ₹16000 at 25% per year for 3 years, compounded every year (in ₹).
40. 40.What is the difference between the compound interest and the simple interest on ₹41600 at 5% per year for 2 years (in ₹)?

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