Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 747 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
2. 2.What amount will ₹35600 grow to in 1 year at 10% per year compound interest (in ₹)?
3. 3.Find the compound interest on ₹19300 at 4% per year for 1 year, compounded every year (in ₹).
4. 4.What is the difference between the compound interest and the simple interest on ₹3200 at 25% per year for 2 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹32100 at 10% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹22000 at 25% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹31000 at 20% per year for 3 years, compounded every year (in ₹).
8. 8.A scooter is worth ₹37200. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
9. 9.What is the difference between the compound interest and the simple interest on ₹9600 at 15% per year for 2 years (in ₹)?
10. 10.A town has 39200 people. The population grows by 20% every year. What will the population be after 2 years?
11. 11.A town has 35000 people. The population grows by 20% every year. What will the population be after 3 years?
12. 12.What is the difference between the compound interest and the simple interest on ₹43600 at 25% per year for 2 years (in ₹)?
13. 13.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
14. 14.What amount will ₹40600 grow to in 1 year at 15% per year compound interest (in ₹)?
15. 15.Find the compound interest on ₹40000 at 20% per year for 3 years, compounded every year (in ₹).
16. 16.A town has 20900 people. The population grows by 15% every year. What will the population be after 1 year?
17. 17.What amount will ₹47500 grow to in 2 years at 4% per year compound interest (in ₹)?
18. 18.A town has 7500 people. The population grows by 12% every year. What will the population be after 2 years?
19. 19.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
20. 20.Find the compound interest on ₹32000 at 5% per year for 1 year, compounded every year (in ₹).
21. 21.Find the compound interest on ₹42900 at 25% per year for 1 year, compounded every year (in ₹).
22. 22.What amount will ₹5600 grow to in 1 year at 12% per year compound interest (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹42500 at 20% per year for 2 years (in ₹)?
24. 24.A scooter is worth ₹57500. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
25. 25.What amount will ₹25200 grow to in 2 years at 5% per year compound interest (in ₹)?
26. 26.A town has 53200 people. The population grows by 15% every year. What will the population be after 2 years?
27. 27.Find the compound interest on ₹54400 at 25% per year for 3 years, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹50400 at 25% per year for 2 years (in ₹)?
29. 29.What amount will ₹49400 grow to in 2 years at 10% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹16000 at 10% per year for 3 years, compounded every year (in ₹).
31. 31.Find the compound interest on ₹45000 at 4% per year for 2 years, compounded every year (in ₹).
32. 32.What is the difference between the compound interest and the simple interest on ₹41200 at 5% per year for 2 years (in ₹)?
33. 33.What is the difference between the compound interest and the simple interest on ₹35900 at 20% per year for 2 years (in ₹)?
34. 34.A town has 30000 people. The population grows by 4% every year. What will the population be after 2 years?
35. 35.A scooter is worth ₹37200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
36. 36.What amount will ₹36900 grow to in 1 year at 8% per year compound interest (in ₹)?
37. 37.Find the compound interest on ₹40300 at 5% per year for 1 year, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹28000 at 15% per year for 2 years (in ₹)?
39. 39.A town has 15600 people. The population grows by 20% every year. What will the population be after 2 years?
40. 40.Find the compound interest on ₹52800 at 5% per year for 2 years, compounded every year (in ₹).

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