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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 749 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A scooter is worth ₹25800. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  2. 2.What amount will ₹42800 grow to in 2 years at 5% per year compound interest (in ₹)?
  3. 3.What amount will ₹39100 grow to in 1 year at 10% per year compound interest (in ₹)?
  4. 4.What amount will ₹35000 grow to in 2 years at 12% per year compound interest (in ₹)?
  5. 5.What amount will ₹30000 grow to in 2 years at 4% per year compound interest (in ₹)?
  6. 6.A scooter is worth ₹27600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  7. 7.Find the compound interest on ₹16000 at 10% per year for 3 years, compounded every year (in ₹).
  8. 8.What is the difference between the compound interest and the simple interest on ₹6500 at 10% per year for 2 years (in ₹)?
  9. 9.What amount will ₹13400 grow to in 2 years at 10% per year compound interest (in ₹)?
  10. 10.Find the compound interest on ₹2600 at 5% per year for 1 year, compounded every year (in ₹).
  11. 11.What amount will ₹35600 grow to in 2 years at 15% per year compound interest (in ₹)?
  12. 12.A scooter is worth ₹38200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
  13. 13.What amount will ₹23400 grow to in 1 year at 25% per year compound interest (in ₹)?
  14. 14.A town has 10800 people. The population grows by 25% every year. What will the population be after 1 year?
  15. 15.What is the difference between the compound interest and the simple interest on ₹56000 at 20% per year for 2 years (in ₹)?
  16. 16.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
  17. 17.A scooter is worth ₹13600. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹32500 at 8% per year for 2 years (in ₹)?
  19. 19.A town has 12800 people. The population grows by 25% every year. What will the population be after 2 years?
  20. 20.What is the difference between the compound interest and the simple interest on ₹24000 at 25% per year for 2 years (in ₹)?
  21. 21.What amount will ₹41200 grow to in 1 year at 20% per year compound interest (in ₹)?
  22. 22.Find the compound interest on ₹57200 at 20% per year for 1 year, compounded every year (in ₹).
  23. 23.What amount will ₹24000 grow to in 3 years at 20% per year compound interest (in ₹)?
  24. 24.What amount will ₹17200 grow to in 1 year at 15% per year compound interest (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹31700 at 10% per year for 2 years (in ₹)?
  26. 26.Find the compound interest on ₹40000 at 15% per year for 3 years, compounded every year (in ₹).
  27. 27.What amount will ₹60000 grow to in 2 years at 12% per year compound interest (in ₹)?
  28. 28.Find the compound interest on ₹11800 at 5% per year for 1 year, compounded every year (in ₹).
  29. 29.A town has 30200 people. The population grows by 4% every year. What will the population be after 1 year?
  30. 30.Find the compound interest on ₹13600 at 4% per year for 1 year, compounded every year (in ₹).
  31. 31.What amount will ₹35900 grow to in 1 year at 8% per year compound interest (in ₹)?
  32. 32.Find the compound interest on ₹57500 at 25% per year for 1 year, compounded every year (in ₹).
  33. 33.Find the compound interest on ₹11200 at 15% per year for 2 years, compounded every year (in ₹).
  34. 34.What amount will ₹4000 grow to in 3 years at 20% per year compound interest (in ₹)?
  35. 35.Find the compound interest on ₹38400 at 8% per year for 1 year, compounded every year (in ₹).
  36. 36.Find the compound interest on ₹51400 at 10% per year for 2 years, compounded every year (in ₹).
  37. 37.A town has 42200 people. The population grows by 20% every year. What will the population be after 1 year?
  38. 38.A town has 49100 people. The population grows by 8% every year. What will the population be after 1 year?
  39. 39.A scooter is worth ₹2800. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
  40. 40.A scooter is worth ₹22300. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?

Answer key

  1. 24510
  2. 47187
  3. 43010
  4. 43904
  5. 32448
  6. 24909
  7. 5296
  8. 65
  9. 16214
  10. 130
  11. 47081
  12. 34380
  13. 29250
  14. 13500
  15. 2240
  16. 144
  17. 12920
  18. 208
  19. 20000
  20. 1500
  21. 49440
  22. 11440
  23. 41472
  24. 19780
  25. 317
  26. 20835
  27. 75264
  28. 590
  29. 31408
  30. 544
  31. 38772
  32. 14375
  33. 3612
  34. 6912
  35. 3072
  36. 10794
  37. 50640
  38. 53028
  39. 2268
  40. 18955

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