Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 752 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹40000 at 8% per year for 2 years, compounded every year (in ₹).
2. 2.A scooter is worth ₹23200. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹55000 at 4% per year for 2 years (in ₹)?
4. 4.A town has 7500 people. The population grows by 4% every year. What will the population be after 2 years?
5. 5.A scooter is worth ₹24000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
6. 6.What amount will ₹16000 grow to in 3 years at 15% per year compound interest (in ₹)?
7. 7.A scooter is worth ₹40200. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
8. 8.A town has 58800 people. The population grows by 5% every year. What will the population be after 2 years?
9. 9.What amount will ₹37500 grow to in 2 years at 8% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹55100 at 20% per year for 2 years, compounded every year (in ₹).
11. 11.What is the difference between the compound interest and the simple interest on ₹39500 at 20% per year for 2 years (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹42500 at 4% per year for 2 years (in ₹)?
13. 13.What is the difference between the compound interest and the simple interest on ₹10400 at 5% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹56400 at 5% per year for 1 year, compounded every year (in ₹).
15. 15.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹24500 at 20% per year for 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹26700 at 10% per year for 2 years (in ₹)?
18. 18.What is the difference between the compound interest and the simple interest on ₹37900 at 10% per year for 2 years (in ₹)?
19. 19.Find the compound interest on ₹58400 at 5% per year for 2 years, compounded every year (in ₹).
20. 20.Find the compound interest on ₹36300 at 8% per year for 1 year, compounded every year (in ₹).
21. 21.A scooter is worth ₹48000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
22. 22.What is the difference between the compound interest and the simple interest on ₹40000 at 4% per year for 2 years (in ₹)?
23. 23.What is the difference between the compound interest and the simple interest on ₹12800 at 15% per year for 2 years (in ₹)?
24. 24.What amount will ₹10300 grow to in 1 year at 20% per year compound interest (in ₹)?
25. 25.What amount will ₹28600 grow to in 2 years at 20% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹20000 at 4% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹18800 at 20% per year for 1 year, compounded every year (in ₹).
28. 28.A town has 20000 people. The population grows by 12% every year. What will the population be after 2 years?
29. 29.What is the difference between the compound interest and the simple interest on ₹20000 at 12% per year for 2 years (in ₹)?
30. 30.What amount will ₹17500 grow to in 2 years at 4% per year compound interest (in ₹)?
31. 31.What is the difference between the compound interest and the simple interest on ₹30000 at 15% per year for 2 years (in ₹)?
32. 32.What amount will ₹49600 grow to in 3 years at 25% per year compound interest (in ₹)?
33. 33.What amount will ₹21600 grow to in 1 year at 8% per year compound interest (in ₹)?
34. 34.A scooter is worth ₹46400. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
35. 35.A scooter is worth ₹15500. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
36. 36.Find the compound interest on ₹43200 at 25% per year for 3 years, compounded every year (in ₹).
37. 37.A town has 11600 people. The population grows by 5% every year. What will the population be after 2 years?
38. 38.A scooter is worth ₹34200. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
39. 39.A town has 55000 people. The population grows by 20% every year. What will the population be after 2 years?
40. 40.What amount will ₹4200 grow to in 1 year at 4% per year compound interest (in ₹)?

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