Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 755 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹24000 at 5% per year for 3 years, compounded every year (in ₹).
2. 2.Find the compound interest on ₹6000 at 15% per year for 2 years, compounded every year (in ₹).
3. 3.Find the compound interest on ₹55600 at 4% per year for 1 year, compounded every year (in ₹).
4. 4.What amount will ₹33900 grow to in 1 year at 25% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹32700 at 4% per year for 1 year, compounded every year (in ₹).
6. 6.Find the compound interest on ₹15000 at 20% per year for 3 years, compounded every year (in ₹).
7. 7.What is the difference between the compound interest and the simple interest on ₹15600 at 5% per year for 2 years (in ₹)?
8. 8.What amount will ₹44000 grow to in 1 year at 12% per year compound interest (in ₹)?
9. 9.Find the compound interest on ₹3000 at 10% per year for 3 years, compounded every year (in ₹).
10. 10.What amount will ₹18300 grow to in 1 year at 8% per year compound interest (in ₹)?
11. 11.A town has 53600 people. The population grows by 5% every year. What will the population be after 2 years?
12. 12.Find the compound interest on ₹10500 at 20% per year for 3 years, compounded every year (in ₹).
13. 13.Find the compound interest on ₹19800 at 20% per year for 1 year, compounded every year (in ₹).
14. 14.What amount will ₹34300 grow to in 1 year at 25% per year compound interest (in ₹)?
15. 15.What is the difference between the compound interest and the simple interest on ₹52500 at 4% per year for 2 years (in ₹)?
16. 16.Find the compound interest on ₹12400 at 25% per year for 2 years, compounded every year (in ₹).
17. 17.Find the compound interest on ₹21000 at 12% per year for 1 year, compounded every year (in ₹).
18. 18.Find the compound interest on ₹56000 at 10% per year for 3 years, compounded every year (in ₹).
19. 19.What amount will ₹40000 grow to in 3 years at 15% per year compound interest (in ₹)?
20. 20.What is the difference between the compound interest and the simple interest on ₹35200 at 15% per year for 2 years (in ₹)?
21. 21.A town has 48000 people. The population grows by 15% every year. What will the population be after 3 years?
22. 22.A town has 55000 people. The population grows by 12% every year. What will the population be after 2 years?
23. 23.A scooter is worth ₹40000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
24. 24.What amount will ₹46400 grow to in 3 years at 25% per year compound interest (in ₹)?
25. 25.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹18800 at 10% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹29900 at 25% per year for 1 year, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹3200 at 5% per year for 2 years (in ₹)?
29. 29.What amount will ₹2500 grow to in 1 year at 4% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹12300 at 15% per year for 1 year, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
32. 32.A town has 52500 people. The population grows by 4% every year. What will the population be after 2 years?
33. 33.Find the compound interest on ₹30000 at 15% per year for 2 years, compounded every year (in ₹).
34. 34.A town has 60000 people. The population grows by 12% every year. What will the population be after 2 years?
35. 35.What amount will ₹59500 grow to in 1 year at 20% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹48000 at 5% per year for 1 year, compounded every year (in ₹).
37. 37.What is the difference between the compound interest and the simple interest on ₹12500 at 20% per year for 2 years (in ₹)?
38. 38.A scooter is worth ₹32000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
39. 39.What amount will ₹41600 grow to in 2 years at 10% per year compound interest (in ₹)?
40. 40.A scooter is worth ₹10000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets