Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 759 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹3000 at 10% per year for 3 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹3600 at 20% per year for 2 years (in ₹)?
3. 3.What amount will ₹32000 grow to in 3 years at 25% per year compound interest (in ₹)?
4. 4.A scooter is worth ₹43500. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
5. 5.What is the difference between the compound interest and the simple interest on ₹41800 at 20% per year for 2 years (in ₹)?
6. 6.What is the difference between the compound interest and the simple interest on ₹45000 at 8% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹48000 at 25% per year for 2 years, compounded every year (in ₹).
8. 8.What is the difference between the compound interest and the simple interest on ₹27600 at 15% per year for 2 years (in ₹)?
9. 9.A town has 59300 people. The population grows by 20% every year. What will the population be after 2 years?
10. 10.What is the difference between the compound interest and the simple interest on ₹25200 at 25% per year for 2 years (in ₹)?
11. 11.What amount will ₹44800 grow to in 2 years at 25% per year compound interest (in ₹)?
12. 12.A town has 55000 people. The population grows by 12% every year. What will the population be after 2 years?
13. 13.A town has 2300 people. The population grows by 5% every year. What will the population be after 1 year?
14. 14.Find the compound interest on ₹59000 at 15% per year for 1 year, compounded every year (in ₹).
15. 15.What amount will ₹3000 grow to in 3 years at 10% per year compound interest (in ₹)?
16. 16.What is the difference between the compound interest and the simple interest on ₹3700 at 10% per year for 2 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹36000 at 10% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹44500 at 20% per year for 3 years, compounded every year (in ₹).
19. 19.What is the difference between the compound interest and the simple interest on ₹46700 at 10% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹5600 at 25% per year for 2 years, compounded every year (in ₹).
21. 21.What amount will ₹38000 grow to in 2 years at 20% per year compound interest (in ₹)?
22. 22.What amount will ₹39400 grow to in 1 year at 12% per year compound interest (in ₹)?
23. 23.A town has 20600 people. The population grows by 25% every year. What will the population be after 1 year?
24. 24.A scooter is worth ₹57400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
25. 25.A town has 16200 people. The population grows by 20% every year. What will the population be after 1 year?
26. 26.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
27. 27.A town has 37200 people. The population grows by 15% every year. What will the population be after 2 years?
28. 28.Find the compound interest on ₹31700 at 20% per year for 1 year, compounded every year (in ₹).
29. 29.What amount will ₹54400 grow to in 2 years at 5% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹16900 at 10% per year for 1 year, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹38800 at 5% per year for 2 years (in ₹)?
32. 32.What amount will ₹30000 grow to in 3 years at 10% per year compound interest (in ₹)?
33. 33.What amount will ₹56000 grow to in 3 years at 25% per year compound interest (in ₹)?
34. 34.A scooter is worth ₹25100. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
35. 35.Find the compound interest on ₹48000 at 5% per year for 3 years, compounded every year (in ₹).
36. 36.Find the compound interest on ₹35500 at 20% per year for 1 year, compounded every year (in ₹).
37. 37.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
38. 38.A town has 58500 people. The population grows by 20% every year. What will the population be after 3 years?
39. 39.What is the difference between the compound interest and the simple interest on ₹4400 at 5% per year for 2 years (in ₹)?
40. 40.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?

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