Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 765 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹37500 at 4% per year for 2 years (in ₹)?
2. 2.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
3. 3.A town has 48000 people. The population grows by 25% every year. What will the population be after 3 years?
4. 4.What is the difference between the compound interest and the simple interest on ₹51500 at 10% per year for 2 years (in ₹)?
5. 5.A town has 21300 people. The population grows by 10% every year. What will the population be after 1 year?
6. 6.What is the difference between the compound interest and the simple interest on ₹60000 at 12% per year for 2 years (in ₹)?
7. 7.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
8. 8.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
9. 9.What amount will ₹42500 grow to in 2 years at 8% per year compound interest (in ₹)?
10. 10.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
11. 11.What amount will ₹23600 grow to in 2 years at 5% per year compound interest (in ₹)?
12. 12.What amount will ₹55000 grow to in 3 years at 10% per year compound interest (in ₹)?
13. 13.Find the compound interest on ₹35000 at 10% per year for 2 years, compounded every year (in ₹).
14. 14.What amount will ₹5000 grow to in 3 years at 10% per year compound interest (in ₹)?
15. 15.A scooter is worth ₹12500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
16. 16.Find the compound interest on ₹6500 at 10% per year for 2 years, compounded every year (in ₹).
17. 17.A town has 19300 people. The population grows by 25% every year. What will the population be after 1 year?
18. 18.What amount will ₹38800 grow to in 2 years at 10% per year compound interest (in ₹)?
19. 19.What is the difference between the compound interest and the simple interest on ₹44000 at 10% per year for 2 years (in ₹)?
20. 20.Find the compound interest on ₹52100 at 10% per year for 1 year, compounded every year (in ₹).
21. 21.A scooter is worth ₹5900. Its value falls by 10% every year. What will it be worth after 2 years (in ₹)?
22. 22.What amount will ₹17200 grow to in 1 year at 5% per year compound interest (in ₹)?
23. 23.Find the compound interest on ₹2500 at 10% per year for 2 years, compounded every year (in ₹).
24. 24.A scooter is worth ₹24500. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
25. 25.Find the compound interest on ₹10000 at 12% per year for 2 years, compounded every year (in ₹).
26. 26.What amount will ₹60000 grow to in 3 years at 10% per year compound interest (in ₹)?
27. 27.Find the compound interest on ₹41600 at 5% per year for 2 years, compounded every year (in ₹).
28. 28.A scooter is worth ₹16400. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
29. 29.What is the difference between the compound interest and the simple interest on ₹22900 at 10% per year for 2 years (in ₹)?
30. 30.Find the compound interest on ₹37500 at 20% per year for 3 years, compounded every year (in ₹).
31. 31.What is the difference between the compound interest and the simple interest on ₹22000 at 5% per year for 2 years (in ₹)?
32. 32.Find the compound interest on ₹17600 at 25% per year for 1 year, compounded every year (in ₹).
33. 33.Find the compound interest on ₹12800 at 10% per year for 2 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹16200 at 4% per year for 1 year, compounded every year (in ₹).
35. 35.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
36. 36.A scooter is worth ₹11500. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
37. 37.Find the compound interest on ₹25600 at 25% per year for 3 years, compounded every year (in ₹).
38. 38.What is the difference between the compound interest and the simple interest on ₹34900 at 20% per year for 2 years (in ₹)?
39. 39.A scooter is worth ₹38500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
40. 40.Find the compound interest on ₹44200 at 25% per year for 1 year, compounded every year (in ₹).

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