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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 77 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.A town has 54000 people. The population grows by 10% every year. What will the population be after 3 years?
  2. 2.A scooter is worth ₹6000. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  3. 3.Find the compound interest on ₹17500 at 4% per year for 2 years, compounded every year (in ₹).
  4. 4.A town has 41000 people. The population grows by 20% every year. What will the population be after 1 year?
  5. 5.Find the compound interest on ₹25000 at 8% per year for 2 years, compounded every year (in ₹).
  6. 6.What is the difference between the compound interest and the simple interest on ₹58800 at 25% per year for 2 years (in ₹)?
  7. 7.What amount will ₹47000 grow to in 1 year at 4% per year compound interest (in ₹)?
  8. 8.A scooter is worth ₹55000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  9. 9.Find the compound interest on ₹15100 at 10% per year for 1 year, compounded every year (in ₹).
  10. 10.What is the difference between the compound interest and the simple interest on ₹57600 at 15% per year for 2 years (in ₹)?
  11. 11.Find the compound interest on ₹11500 at 20% per year for 1 year, compounded every year (in ₹).
  12. 12.What is the difference between the compound interest and the simple interest on ₹57400 at 10% per year for 2 years (in ₹)?
  13. 13.A scooter is worth ₹10800. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  14. 14.What amount will ₹57000 grow to in 3 years at 20% per year compound interest (in ₹)?
  15. 15.What amount will ₹52500 grow to in 2 years at 4% per year compound interest (in ₹)?
  16. 16.What amount will ₹13600 grow to in 1 year at 15% per year compound interest (in ₹)?
  17. 17.Find the compound interest on ₹24000 at 15% per year for 3 years, compounded every year (in ₹).
  18. 18.Find the compound interest on ₹10100 at 10% per year for 2 years, compounded every year (in ₹).
  19. 19.Find the compound interest on ₹39700 at 25% per year for 1 year, compounded every year (in ₹).
  20. 20.Find the compound interest on ₹51200 at 8% per year for 1 year, compounded every year (in ₹).
  21. 21.Find the compound interest on ₹2500 at 20% per year for 3 years, compounded every year (in ₹).
  22. 22.Find the compound interest on ₹55600 at 8% per year for 1 year, compounded every year (in ₹).
  23. 23.A town has 52800 people. The population grows by 10% every year. What will the population be after 1 year?
  24. 24.Find the compound interest on ₹38000 at 5% per year for 1 year, compounded every year (in ₹).
  25. 25.What amount will ₹17600 grow to in 1 year at 8% per year compound interest (in ₹)?
  26. 26.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
  27. 27.A town has 45100 people. The population grows by 10% every year. What will the population be after 2 years?
  28. 28.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  29. 29.What amount will ₹55500 grow to in 3 years at 20% per year compound interest (in ₹)?
  30. 30.A scooter is worth ₹19200. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  31. 31.What amount will ₹17300 grow to in 2 years at 10% per year compound interest (in ₹)?
  32. 32.Find the compound interest on ₹56600 at 20% per year for 2 years, compounded every year (in ₹).
  33. 33.What amount will ₹40500 grow to in 1 year at 8% per year compound interest (in ₹)?
  34. 34.Find the compound interest on ₹45000 at 12% per year for 2 years, compounded every year (in ₹).
  35. 35.What is the difference between the compound interest and the simple interest on ₹10000 at 4% per year for 2 years (in ₹)?
  36. 36.Find the compound interest on ₹11800 at 4% per year for 1 year, compounded every year (in ₹).
  37. 37.A town has 48400 people. The population grows by 12% every year. What will the population be after 1 year?
  38. 38.What is the difference between the compound interest and the simple interest on ₹54800 at 20% per year for 2 years (in ₹)?
  39. 39.What amount will ₹4600 grow to in 1 year at 20% per year compound interest (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹16700 at 10% per year for 2 years (in ₹)?

Answer key

  1. 71874
  2. 4335
  3. 1428
  4. 49200
  5. 4160
  6. 3675
  7. 48880
  8. 46552
  9. 1510
  10. 1296
  11. 2300
  12. 574
  13. 9747
  14. 98496
  15. 56784
  16. 15640
  17. 12501
  18. 2121
  19. 9925
  20. 4096
  21. 1820
  22. 4448
  23. 58080
  24. 1900
  25. 19008
  26. 48668
  27. 54571
  28. 2522
  29. 95904
  30. 16320
  31. 20933
  32. 24904
  33. 43740
  34. 11448
  35. 16
  36. 472
  37. 54208
  38. 2192
  39. 5520
  40. 167

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