Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 770 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.Find the compound interest on ₹33000 at 10% per year for 3 years, compounded every year (in ₹).
2. 2.What is the difference between the compound interest and the simple interest on ₹2500 at 12% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹35000 at 8% per year for 2 years (in ₹)?
4. 4.A town has 57500 people. The population grows by 15% every year. What will the population be after 1 year?
5. 5.Find the compound interest on ₹17500 at 8% per year for 2 years, compounded every year (in ₹).
6. 6.Find the compound interest on ₹58500 at 10% per year for 1 year, compounded every year (in ₹).
7. 7.A town has 36000 people. The population grows by 10% every year. What will the population be after 3 years?
8. 8.A town has 32000 people. The population grows by 15% every year. What will the population be after 3 years?
9. 9.What amount will ₹17500 grow to in 3 years at 20% per year compound interest (in ₹)?
10. 10.What amount will ₹6800 grow to in 2 years at 10% per year compound interest (in ₹)?
11. 11.What amount will ₹8800 grow to in 2 years at 10% per year compound interest (in ₹)?
12. 12.What is the difference between the compound interest and the simple interest on ₹14000 at 25% per year for 2 years (in ₹)?
13. 13.A town has 24000 people. The population grows by 5% every year. What will the population be after 3 years?
14. 14.A scooter is worth ₹24000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
15. 15.Find the compound interest on ₹10900 at 4% per year for 1 year, compounded every year (in ₹).
16. 16.A scooter is worth ₹58000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
17. 17.What is the difference between the compound interest and the simple interest on ₹45500 at 10% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹24900 at 20% per year for 2 years, compounded every year (in ₹).
19. 19.A scooter is worth ₹35500. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
20. 20.Find the compound interest on ₹5000 at 10% per year for 3 years, compounded every year (in ₹).
21. 21.A town has 58600 people. The population grows by 20% every year. What will the population be after 2 years?
22. 22.Find the compound interest on ₹48900 at 10% per year for 2 years, compounded every year (in ₹).
23. 23.Find the compound interest on ₹13600 at 5% per year for 2 years, compounded every year (in ₹).
24. 24.A town has 8000 people. The population grows by 5% every year. What will the population be after 1 year?
25. 25.Find the compound interest on ₹40000 at 12% per year for 2 years, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹6400 at 15% per year for 2 years (in ₹)?
27. 27.A scooter is worth ₹19900. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
28. 28.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
29. 29.What amount will ₹17500 grow to in 2 years at 8% per year compound interest (in ₹)?
30. 30.A town has 20000 people. The population grows by 8% every year. What will the population be after 2 years?
31. 31.A town has 23000 people. The population grows by 8% every year. What will the population be after 1 year?
32. 32.What is the difference between the compound interest and the simple interest on ₹16200 at 20% per year for 2 years (in ₹)?
33. 33.Find the compound interest on ₹49100 at 20% per year for 2 years, compounded every year (in ₹).
34. 34.Find the compound interest on ₹30000 at 8% per year for 2 years, compounded every year (in ₹).
35. 35.What amount will ₹10000 grow to in 2 years at 12% per year compound interest (in ₹)?
36. 36.Find the compound interest on ₹8300 at 5% per year for 1 year, compounded every year (in ₹).
37. 37.A scooter is worth ₹12500. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
38. 38.What amount will ₹2600 grow to in 1 year at 5% per year compound interest (in ₹)?
39. 39.What amount will ₹13200 grow to in 2 years at 5% per year compound interest (in ₹)?
40. 40.What amount will ₹37000 grow to in 3 years at 10% per year compound interest (in ₹)?

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