Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.What is the difference between the compound interest and the simple interest on ₹59200 at 5% per year for 2 years (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹24000 at 5% per year for 2 years (in ₹)?
- 3.Find the compound interest on ₹57000 at 10% per year for 3 years, compounded every year (in ₹).
- 4.What is the difference between the compound interest and the simple interest on ₹39600 at 25% per year for 2 years (in ₹)?
- 5.What amount will ₹19200 grow to in 3 years at 25% per year compound interest (in ₹)?
- 6.What amount will ₹55800 grow to in 1 year at 15% per year compound interest (in ₹)?
- 7.A town has 14500 people. The population grows by 12% every year. What will the population be after 1 year?
- 8.What is the difference between the compound interest and the simple interest on ₹34800 at 25% per year for 2 years (in ₹)?
- 9.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 10.What amount will ₹22000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 11.A town has 25600 people. The population grows by 25% every year. What will the population be after 3 years?
- 12.A scooter is worth ₹44800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
- 13.A town has 31000 people. The population grows by 10% every year. What will the population be after 3 years?
- 14.What amount will ₹8900 grow to in 1 year at 20% per year compound interest (in ₹)?
- 15.What amount will ₹43900 grow to in 1 year at 25% per year compound interest (in ₹)?
- 16.A scooter is worth ₹45000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 17.A scooter is worth ₹18300. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 18.What is the difference between the compound interest and the simple interest on ₹30000 at 15% per year for 2 years (in ₹)?
- 19.Find the compound interest on ₹54800 at 15% per year for 2 years, compounded every year (in ₹).
- 20.What amount will ₹39900 grow to in 1 year at 25% per year compound interest (in ₹)?
- 21.A town has 35600 people. The population grows by 20% every year. What will the population be after 1 year?
- 22.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 23.A scooter is worth ₹15600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 24.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
- 25.A town has 29500 people. The population grows by 10% every year. What will the population be after 2 years?
- 26.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
- 27.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 28.What amount will ₹55000 grow to in 2 years at 12% per year compound interest (in ₹)?
- 29.What is the difference between the compound interest and the simple interest on ₹47400 at 20% per year for 2 years (in ₹)?
- 30.What amount will ₹31700 grow to in 1 year at 15% per year compound interest (in ₹)?
- 31.What amount will ₹32300 grow to in 1 year at 10% per year compound interest (in ₹)?
- 32.Find the compound interest on ₹32500 at 8% per year for 2 years, compounded every year (in ₹).
- 33.What is the difference between the compound interest and the simple interest on ₹48800 at 5% per year for 2 years (in ₹)?
- 34.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
- 35.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 36.What is the difference between the compound interest and the simple interest on ₹39200 at 15% per year for 2 years (in ₹)?
- 37.A town has 17200 people. The population grows by 5% every year. What will the population be after 2 years?
- 38.Find the compound interest on ₹58500 at 25% per year for 1 year, compounded every year (in ₹).
- 39.A town has 32000 people. The population grows by 10% every year. What will the population be after 3 years?
- 40.Find the compound interest on ₹54000 at 10% per year for 3 years, compounded every year (in ₹).
Answer key
- 148
- 60
- 18867
- 2475
- 37500
- 64170
- 16240
- 2175
- 64827
- 38016
- 50000
- 32368
- 41261
- 10680
- 54875
- 38088
- 17568
- 675
- 17673
- 49875
- 42720
- 36501
- 14079
- 8904
- 35695
- 504
- 48668
- 68992
- 1896
- 36455
- 35530
- 5408
- 122
- 1261
- 18522
- 882
- 18963
- 14625
- 42592
- 17874
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