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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 772 · 40 sums
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The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.What is the difference between the compound interest and the simple interest on ₹59200 at 5% per year for 2 years (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹24000 at 5% per year for 2 years (in ₹)?
  3. 3.Find the compound interest on ₹57000 at 10% per year for 3 years, compounded every year (in ₹).
  4. 4.What is the difference between the compound interest and the simple interest on ₹39600 at 25% per year for 2 years (in ₹)?
  5. 5.What amount will ₹19200 grow to in 3 years at 25% per year compound interest (in ₹)?
  6. 6.What amount will ₹55800 grow to in 1 year at 15% per year compound interest (in ₹)?
  7. 7.A town has 14500 people. The population grows by 12% every year. What will the population be after 1 year?
  8. 8.What is the difference between the compound interest and the simple interest on ₹34800 at 25% per year for 2 years (in ₹)?
  9. 9.What amount will ₹56000 grow to in 3 years at 5% per year compound interest (in ₹)?
  10. 10.What amount will ₹22000 grow to in 3 years at 20% per year compound interest (in ₹)?
  11. 11.A town has 25600 people. The population grows by 25% every year. What will the population be after 3 years?
  12. 12.A scooter is worth ₹44800. Its value falls by 15% every year. What will it be worth after 2 years (in ₹)?
  13. 13.A town has 31000 people. The population grows by 10% every year. What will the population be after 3 years?
  14. 14.What amount will ₹8900 grow to in 1 year at 20% per year compound interest (in ₹)?
  15. 15.What amount will ₹43900 grow to in 1 year at 25% per year compound interest (in ₹)?
  16. 16.A scooter is worth ₹45000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  17. 17.A scooter is worth ₹18300. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
  18. 18.What is the difference between the compound interest and the simple interest on ₹30000 at 15% per year for 2 years (in ₹)?
  19. 19.Find the compound interest on ₹54800 at 15% per year for 2 years, compounded every year (in ₹).
  20. 20.What amount will ₹39900 grow to in 1 year at 25% per year compound interest (in ₹)?
  21. 21.A town has 35600 people. The population grows by 20% every year. What will the population be after 1 year?
  22. 22.What amount will ₹24000 grow to in 3 years at 15% per year compound interest (in ₹)?
  23. 23.A scooter is worth ₹15600. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  24. 24.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
  25. 25.A town has 29500 people. The population grows by 10% every year. What will the population be after 2 years?
  26. 26.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
  27. 27.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
  28. 28.What amount will ₹55000 grow to in 2 years at 12% per year compound interest (in ₹)?
  29. 29.What is the difference between the compound interest and the simple interest on ₹47400 at 20% per year for 2 years (in ₹)?
  30. 30.What amount will ₹31700 grow to in 1 year at 15% per year compound interest (in ₹)?
  31. 31.What amount will ₹32300 grow to in 1 year at 10% per year compound interest (in ₹)?
  32. 32.Find the compound interest on ₹32500 at 8% per year for 2 years, compounded every year (in ₹).
  33. 33.What is the difference between the compound interest and the simple interest on ₹48800 at 5% per year for 2 years (in ₹)?
  34. 34.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
  35. 35.What amount will ₹16000 grow to in 3 years at 5% per year compound interest (in ₹)?
  36. 36.What is the difference between the compound interest and the simple interest on ₹39200 at 15% per year for 2 years (in ₹)?
  37. 37.A town has 17200 people. The population grows by 5% every year. What will the population be after 2 years?
  38. 38.Find the compound interest on ₹58500 at 25% per year for 1 year, compounded every year (in ₹).
  39. 39.A town has 32000 people. The population grows by 10% every year. What will the population be after 3 years?
  40. 40.Find the compound interest on ₹54000 at 10% per year for 3 years, compounded every year (in ₹).

Answer key

  1. 148
  2. 60
  3. 18867
  4. 2475
  5. 37500
  6. 64170
  7. 16240
  8. 2175
  9. 64827
  10. 38016
  11. 50000
  12. 32368
  13. 41261
  14. 10680
  15. 54875
  16. 38088
  17. 17568
  18. 675
  19. 17673
  20. 49875
  21. 42720
  22. 36501
  23. 14079
  24. 8904
  25. 35695
  26. 504
  27. 48668
  28. 68992
  29. 1896
  30. 36455
  31. 35530
  32. 5408
  33. 122
  34. 1261
  35. 18522
  36. 882
  37. 18963
  38. 14625
  39. 42592
  40. 17874

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