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Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 774 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

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  1. 1.What is the difference between the compound interest and the simple interest on ₹56800 at 5% per year for 2 years (in ₹)?
  2. 2.A town has 8000 people. The population grows by 5% every year. What will the population be after 3 years?
  3. 3.What is the difference between the compound interest and the simple interest on ₹40800 at 25% per year for 2 years (in ₹)?
  4. 4.A scooter is worth ₹7500. Its value falls by 12% every year. What will it be worth after 2 years (in ₹)?
  5. 5.What amount will ₹43200 grow to in 2 years at 5% per year compound interest (in ₹)?
  6. 6.A scooter is worth ₹42500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
  7. 7.What amount will ₹20000 grow to in 2 years at 4% per year compound interest (in ₹)?
  8. 8.Find the compound interest on ₹46300 at 10% per year for 2 years, compounded every year (in ₹).
  9. 9.What amount will ₹8500 grow to in 1 year at 5% per year compound interest (in ₹)?
  10. 10.Find the compound interest on ₹59600 at 20% per year for 2 years, compounded every year (in ₹).
  11. 11.What is the difference between the compound interest and the simple interest on ₹48900 at 10% per year for 2 years (in ₹)?
  12. 12.Find the compound interest on ₹47600 at 25% per year for 1 year, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹51800 at 10% per year for 2 years, compounded every year (in ₹).
  14. 14.What is the difference between the compound interest and the simple interest on ₹16400 at 25% per year for 2 years (in ₹)?
  15. 15.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
  16. 16.Find the compound interest on ₹16000 at 5% per year for 3 years, compounded every year (in ₹).
  17. 17.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
  18. 18.A scooter is worth ₹3400. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  19. 19.What is the difference between the compound interest and the simple interest on ₹32800 at 5% per year for 2 years (in ₹)?
  20. 20.Find the compound interest on ₹22300 at 20% per year for 2 years, compounded every year (in ₹).
  21. 21.A town has 53700 people. The population grows by 15% every year. What will the population be after 1 year?
  22. 22.A scooter is worth ₹18300. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  23. 23.What amount will ₹53400 grow to in 1 year at 20% per year compound interest (in ₹)?
  24. 24.A scooter is worth ₹55300. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
  25. 25.What is the difference between the compound interest and the simple interest on ₹22500 at 10% per year for 2 years (in ₹)?
  26. 26.What is the difference between the compound interest and the simple interest on ₹28900 at 10% per year for 2 years (in ₹)?
  27. 27.What amount will ₹24500 grow to in 1 year at 20% per year compound interest (in ₹)?
  28. 28.What is the difference between the compound interest and the simple interest on ₹52100 at 20% per year for 2 years (in ₹)?
  29. 29.A town has 35700 people. The population grows by 20% every year. What will the population be after 2 years?
  30. 30.Find the compound interest on ₹58400 at 4% per year for 1 year, compounded every year (in ₹).
  31. 31.A scooter is worth ₹12300. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
  32. 32.A town has 48000 people. The population grows by 5% every year. What will the population be after 3 years?
  33. 33.Find the compound interest on ₹6500 at 5% per year for 1 year, compounded every year (in ₹).
  34. 34.Find the compound interest on ₹23600 at 25% per year for 2 years, compounded every year (in ₹).
  35. 35.Find the compound interest on ₹45900 at 25% per year for 1 year, compounded every year (in ₹).
  36. 36.Find the compound interest on ₹38300 at 12% per year for 1 year, compounded every year (in ₹).
  37. 37.What amount will ₹47500 grow to in 2 years at 12% per year compound interest (in ₹)?
  38. 38.What is the difference between the compound interest and the simple interest on ₹15000 at 12% per year for 2 years (in ₹)?
  39. 39.Find the compound interest on ₹20800 at 25% per year for 3 years, compounded every year (in ₹).
  40. 40.What amount will ₹30400 grow to in 2 years at 25% per year compound interest (in ₹)?

Answer key

  1. 142
  2. 9261
  3. 2550
  4. 5808
  5. 47628
  6. 35972
  7. 21632
  8. 9723
  9. 8925
  10. 26224
  11. 489
  12. 11900
  13. 10878
  14. 1025
  15. 8827
  16. 2522
  17. 29169
  18. 2550
  19. 82
  20. 9812
  21. 61755
  22. 14640
  23. 64080
  24. 44240
  25. 225
  26. 289
  27. 29400
  28. 2084
  29. 51408
  30. 2336
  31. 9225
  32. 55566
  33. 325
  34. 13275
  35. 11475
  36. 4596
  37. 59584
  38. 216
  39. 19825
  40. 47500

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