Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
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- 1.What amount will ₹34300 grow to in 1 year at 8% per year compound interest (in ₹)?
- 2.Find the compound interest on ₹30900 at 25% per year for 1 year, compounded every year (in ₹).
- 3.What amount will ₹31700 grow to in 1 year at 12% per year compound interest (in ₹)?
- 4.Find the compound interest on ₹54400 at 5% per year for 2 years, compounded every year (in ₹).
- 5.What is the difference between the compound interest and the simple interest on ₹24400 at 5% per year for 2 years (in ₹)?
- 6.A town has 34900 people. The population grows by 25% every year. What will the population be after 1 year?
- 7.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
- 8.A town has 39000 people. The population grows by 10% every year. What will the population be after 3 years?
- 9.A town has 12100 people. The population grows by 4% every year. What will the population be after 1 year?
- 10.What amount will ₹31200 grow to in 1 year at 10% per year compound interest (in ₹)?
- 11.A town has 2900 people. The population grows by 8% every year. What will the population be after 1 year?
- 12.A scooter is worth ₹21800. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
- 13.Find the compound interest on ₹54400 at 25% per year for 3 years, compounded every year (in ₹).
- 14.A scooter is worth ₹26000. Its value falls by 10% every year. What will it be worth after 3 years (in ₹)?
- 15.A town has 18000 people. The population grows by 5% every year. What will the population be after 2 years?
- 16.What amount will ₹12500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 17.What is the difference between the compound interest and the simple interest on ₹50000 at 4% per year for 2 years (in ₹)?
- 18.A scooter is worth ₹6000. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 19.What is the difference between the compound interest and the simple interest on ₹6900 at 10% per year for 2 years (in ₹)?
- 20.A town has 22000 people. The population grows by 5% every year. What will the population be after 2 years?
- 21.Find the compound interest on ₹40000 at 25% per year for 1 year, compounded every year (in ₹).
- 22.What is the difference between the compound interest and the simple interest on ₹22500 at 8% per year for 2 years (in ₹)?
- 23.What is the difference between the compound interest and the simple interest on ₹40800 at 15% per year for 2 years (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹47500 at 4% per year for 2 years (in ₹)?
- 25.What amount will ₹3100 grow to in 1 year at 4% per year compound interest (in ₹)?
- 26.Find the compound interest on ₹35200 at 25% per year for 3 years, compounded every year (in ₹).
- 27.Find the compound interest on ₹42500 at 4% per year for 2 years, compounded every year (in ₹).
- 28.What is the difference between the compound interest and the simple interest on ₹45600 at 25% per year for 2 years (in ₹)?
- 29.Find the compound interest on ₹48300 at 10% per year for 2 years, compounded every year (in ₹).
- 30.What is the difference between the compound interest and the simple interest on ₹51600 at 10% per year for 2 years (in ₹)?
- 31.What amount will ₹60000 grow to in 2 years at 8% per year compound interest (in ₹)?
- 32.What amount will ₹32000 grow to in 3 years at 15% per year compound interest (in ₹)?
- 33.What is the difference between the compound interest and the simple interest on ₹56400 at 15% per year for 2 years (in ₹)?
- 34.A scooter is worth ₹22000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
- 35.What amount will ₹37300 grow to in 1 year at 15% per year compound interest (in ₹)?
- 36.Find the compound interest on ₹41200 at 15% per year for 1 year, compounded every year (in ₹).
- 37.What amount will ₹55900 grow to in 1 year at 12% per year compound interest (in ₹)?
- 38.A town has 56000 people. The population grows by 5% every year. What will the population be after 3 years?
- 39.A scooter is worth ₹57500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
- 40.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
Answer key
- 37044
- 7725
- 35504
- 5576
- 61
- 43625
- 29169
- 51909
- 12584
- 34320
- 3132
- 19620
- 51850
- 18954
- 19845
- 15680
- 80
- 5415
- 69
- 24255
- 10000
- 144
- 918
- 76
- 3224
- 33550
- 3468
- 2850
- 10143
- 516
- 69984
- 48668
- 1269
- 12375
- 42895
- 6180
- 62608
- 64827
- 48668
- 1261
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