Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 785 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What amount will ₹15000 grow to in 3 years at 10% per year compound interest (in ₹)?
2. 2.What amount will ₹39600 grow to in 2 years at 10% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹12500 at 4% per year for 2 years (in ₹)?
4. 4.Find the compound interest on ₹40000 at 5% per year for 3 years, compounded every year (in ₹).
5. 5.Find the compound interest on ₹56000 at 15% per year for 3 years, compounded every year (in ₹).
6. 6.What amount will ₹11200 grow to in 3 years at 25% per year compound interest (in ₹)?
7. 7.What is the difference between the compound interest and the simple interest on ₹28000 at 5% per year for 2 years (in ₹)?
8. 8.A scooter is worth ₹12500. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
9. 9.What amount will ₹17500 grow to in 2 years at 4% per year compound interest (in ₹)?
10. 10.What is the difference between the compound interest and the simple interest on ₹46800 at 5% per year for 2 years (in ₹)?
11. 11.Find the compound interest on ₹25000 at 4% per year for 2 years, compounded every year (in ₹).
12. 12.Find the compound interest on ₹30000 at 12% per year for 2 years, compounded every year (in ₹).
13. 13.What is the difference between the compound interest and the simple interest on ₹6000 at 15% per year for 2 years (in ₹)?
14. 14.Find the compound interest on ₹7000 at 10% per year for 3 years, compounded every year (in ₹).
15. 15.Find the compound interest on ₹6700 at 10% per year for 2 years, compounded every year (in ₹).
16. 16.What is the difference between the compound interest and the simple interest on ₹25000 at 8% per year for 2 years (in ₹)?
17. 17.Find the compound interest on ₹25400 at 25% per year for 1 year, compounded every year (in ₹).
18. 18.Find the compound interest on ₹53200 at 20% per year for 2 years, compounded every year (in ₹).
19. 19.A town has 15000 people. The population grows by 12% every year. What will the population be after 2 years?
20. 20.What is the difference between the compound interest and the simple interest on ₹2500 at 4% per year for 2 years (in ₹)?
21. 21.Find the compound interest on ₹8400 at 15% per year for 2 years, compounded every year (in ₹).
22. 22.Find the compound interest on ₹2500 at 12% per year for 2 years, compounded every year (in ₹).
23. 23.A town has 47500 people. The population grows by 4% every year. What will the population be after 2 years?
24. 24.A town has 20600 people. The population grows by 20% every year. What will the population be after 2 years?
25. 25.What amount will ₹5500 grow to in 1 year at 15% per year compound interest (in ₹)?
26. 26.What is the difference between the compound interest and the simple interest on ₹2400 at 15% per year for 2 years (in ₹)?
27. 27.Find the compound interest on ₹9900 at 20% per year for 1 year, compounded every year (in ₹).
28. 28.What is the difference between the compound interest and the simple interest on ₹18400 at 25% per year for 2 years (in ₹)?
29. 29.Find the compound interest on ₹34400 at 25% per year for 2 years, compounded every year (in ₹).
30. 30.A town has 4200 people. The population grows by 20% every year. What will the population be after 1 year?
31. 31.Find the compound interest on ₹17500 at 12% per year for 2 years, compounded every year (in ₹).
32. 32.A scooter is worth ₹4000. Its value falls by 25% every year. What will it be worth after 2 years (in ₹)?
33. 33.Find the compound interest on ₹5100 at 5% per year for 1 year, compounded every year (in ₹).
34. 34.What is the difference between the compound interest and the simple interest on ₹32500 at 4% per year for 2 years (in ₹)?
35. 35.A scooter is worth ₹16000. Its value falls by 15% every year. What will it be worth after 3 years (in ₹)?
36. 36.Find the compound interest on ₹4000 at 15% per year for 2 years, compounded every year (in ₹).
37. 37.What amount will ₹16000 grow to in 2 years at 10% per year compound interest (in ₹)?
38. 38.A scooter is worth ₹8000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
39. 39.Find the compound interest on ₹33600 at 25% per year for 3 years, compounded every year (in ₹).
40. 40.Find the compound interest on ₹56500 at 12% per year for 1 year, compounded every year (in ₹).

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