Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.A scooter is worth ₹38800. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
- 2.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
- 3.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
- 4.A town has 2500 people. The population grows by 8% every year. What will the population be after 2 years?
- 5.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
- 6.A town has 20800 people. The population grows by 25% every year. What will the population be after 2 years?
- 7.What is the difference between the compound interest and the simple interest on ₹40900 at 10% per year for 2 years (in ₹)?
- 8.What is the difference between the compound interest and the simple interest on ₹13400 at 10% per year for 2 years (in ₹)?
- 9.What amount will ₹15400 grow to in 2 years at 20% per year compound interest (in ₹)?
- 10.Find the compound interest on ₹29500 at 15% per year for 1 year, compounded every year (in ₹).
- 11.A town has 7500 people. The population grows by 12% every year. What will the population be after 2 years?
- 12.Find the compound interest on ₹5000 at 8% per year for 2 years, compounded every year (in ₹).
- 13.Find the compound interest on ₹39500 at 10% per year for 1 year, compounded every year (in ₹).
- 14.A town has 22100 people. The population grows by 15% every year. What will the population be after 1 year?
- 15.What is the difference between the compound interest and the simple interest on ₹4000 at 25% per year for 2 years (in ₹)?
- 16.A town has 31500 people. The population grows by 20% every year. What will the population be after 3 years?
- 17.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
- 18.A town has 47800 people. The population grows by 4% every year. What will the population be after 1 year?
- 19.Find the compound interest on ₹32200 at 5% per year for 1 year, compounded every year (in ₹).
- 20.A town has 4500 people. The population grows by 20% every year. What will the population be after 3 years?
- 21.What amount will ₹57500 grow to in 2 years at 4% per year compound interest (in ₹)?
- 22.A town has 51100 people. The population grows by 5% every year. What will the population be after 1 year?
- 23.Find the compound interest on ₹9600 at 10% per year for 1 year, compounded every year (in ₹).
- 24.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
- 25.Find the compound interest on ₹58400 at 15% per year for 2 years, compounded every year (in ₹).
- 26.What is the difference between the compound interest and the simple interest on ₹31600 at 25% per year for 2 years (in ₹)?
- 27.Find the compound interest on ₹35200 at 5% per year for 2 years, compounded every year (in ₹).
- 28.Find the compound interest on ₹43700 at 10% per year for 1 year, compounded every year (in ₹).
- 29.A town has 2500 people. The population grows by 4% every year. What will the population be after 2 years?
- 30.A scooter is worth ₹6400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
- 31.A town has 54200 people. The population grows by 8% every year. What will the population be after 1 year?
- 32.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
- 33.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
- 34.A scooter is worth ₹36600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 35.A town has 5000 people. The population grows by 12% every year. What will the population be after 2 years?
- 36.What amount will ₹19000 grow to in 1 year at 5% per year compound interest (in ₹)?
- 37.What amount will ₹6000 grow to in 2 years at 15% per year compound interest (in ₹)?
- 38.A town has 55200 people. The population grows by 5% every year. What will the population be after 2 years?
- 39.What amount will ₹46800 grow to in 2 years at 20% per year compound interest (in ₹)?
- 40.What is the difference between the compound interest and the simple interest on ₹56400 at 25% per year for 2 years (in ₹)?
Answer key
- 36860
- 176
- 72
- 2916
- 8827
- 32500
- 409
- 134
- 22176
- 4425
- 9408
- 832
- 3950
- 25415
- 250
- 54432
- 4167
- 49712
- 1610
- 7776
- 62192
- 53655
- 960
- 20577
- 18834
- 1975
- 3608
- 4370
- 2704
- 5776
- 58536
- 612
- 65856
- 31110
- 6272
- 19950
- 7935
- 60858
- 67392
- 3525
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