← Compound interest lesson New set →

Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 789 · 40 sums
TalentJR

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

NameDateTime takenScore ___ / 40
  1. 1.A scooter is worth ₹38800. Its value falls by 5% every year. What will it be worth after 1 year (in ₹)?
  2. 2.What is the difference between the compound interest and the simple interest on ₹27500 at 8% per year for 2 years (in ₹)?
  3. 3.What is the difference between the compound interest and the simple interest on ₹5000 at 12% per year for 2 years (in ₹)?
  4. 4.A town has 2500 people. The population grows by 8% every year. What will the population be after 2 years?
  5. 5.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
  6. 6.A town has 20800 people. The population grows by 25% every year. What will the population be after 2 years?
  7. 7.What is the difference between the compound interest and the simple interest on ₹40900 at 10% per year for 2 years (in ₹)?
  8. 8.What is the difference between the compound interest and the simple interest on ₹13400 at 10% per year for 2 years (in ₹)?
  9. 9.What amount will ₹15400 grow to in 2 years at 20% per year compound interest (in ₹)?
  10. 10.Find the compound interest on ₹29500 at 15% per year for 1 year, compounded every year (in ₹).
  11. 11.A town has 7500 people. The population grows by 12% every year. What will the population be after 2 years?
  12. 12.Find the compound interest on ₹5000 at 8% per year for 2 years, compounded every year (in ₹).
  13. 13.Find the compound interest on ₹39500 at 10% per year for 1 year, compounded every year (in ₹).
  14. 14.A town has 22100 people. The population grows by 15% every year. What will the population be after 1 year?
  15. 15.What is the difference between the compound interest and the simple interest on ₹4000 at 25% per year for 2 years (in ₹)?
  16. 16.A town has 31500 people. The population grows by 20% every year. What will the population be after 3 years?
  17. 17.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
  18. 18.A town has 47800 people. The population grows by 4% every year. What will the population be after 1 year?
  19. 19.Find the compound interest on ₹32200 at 5% per year for 1 year, compounded every year (in ₹).
  20. 20.A town has 4500 people. The population grows by 20% every year. What will the population be after 3 years?
  21. 21.What amount will ₹57500 grow to in 2 years at 4% per year compound interest (in ₹)?
  22. 22.A town has 51100 people. The population grows by 5% every year. What will the population be after 1 year?
  23. 23.Find the compound interest on ₹9600 at 10% per year for 1 year, compounded every year (in ₹).
  24. 24.A scooter is worth ₹24000. Its value falls by 5% every year. What will it be worth after 3 years (in ₹)?
  25. 25.Find the compound interest on ₹58400 at 15% per year for 2 years, compounded every year (in ₹).
  26. 26.What is the difference between the compound interest and the simple interest on ₹31600 at 25% per year for 2 years (in ₹)?
  27. 27.Find the compound interest on ₹35200 at 5% per year for 2 years, compounded every year (in ₹).
  28. 28.Find the compound interest on ₹43700 at 10% per year for 1 year, compounded every year (in ₹).
  29. 29.A town has 2500 people. The population grows by 4% every year. What will the population be after 2 years?
  30. 30.A scooter is worth ₹6400. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
  31. 31.A town has 54200 people. The population grows by 8% every year. What will the population be after 1 year?
  32. 32.What is the difference between the compound interest and the simple interest on ₹42500 at 12% per year for 2 years (in ₹)?
  33. 33.What amount will ₹52500 grow to in 2 years at 12% per year compound interest (in ₹)?
  34. 34.A scooter is worth ₹36600. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
  35. 35.A town has 5000 people. The population grows by 12% every year. What will the population be after 2 years?
  36. 36.What amount will ₹19000 grow to in 1 year at 5% per year compound interest (in ₹)?
  37. 37.What amount will ₹6000 grow to in 2 years at 15% per year compound interest (in ₹)?
  38. 38.A town has 55200 people. The population grows by 5% every year. What will the population be after 2 years?
  39. 39.What amount will ₹46800 grow to in 2 years at 20% per year compound interest (in ₹)?
  40. 40.What is the difference between the compound interest and the simple interest on ₹56400 at 25% per year for 2 years (in ₹)?

Answer key

  1. 36860
  2. 176
  3. 72
  4. 2916
  5. 8827
  6. 32500
  7. 409
  8. 134
  9. 22176
  10. 4425
  11. 9408
  12. 832
  13. 3950
  14. 25415
  15. 250
  16. 54432
  17. 4167
  18. 49712
  19. 1610
  20. 7776
  21. 62192
  22. 53655
  23. 960
  24. 20577
  25. 18834
  26. 1975
  27. 3608
  28. 4370
  29. 2704
  30. 5776
  31. 58536
  32. 612
  33. 65856
  34. 31110
  35. 6272
  36. 19950
  37. 7935
  38. 60858
  39. 67392
  40. 3525

Free maths worksheets lessons, practice and worksheets at talentjr.in/maths-worksheets