Class 8 Maths Worksheet: Compound Interest
The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.
NameDateTime takenScore ___ / 40
- 1.Find the compound interest on ₹40600 at 4% per year for 1 year, compounded every year (in ₹).
- 2.Find the compound interest on ₹12500 at 20% per year for 2 years, compounded every year (in ₹).
- 3.Find the compound interest on ₹10000 at 12% per year for 2 years, compounded every year (in ₹).
- 4.What amount will ₹22500 grow to in 1 year at 10% per year compound interest (in ₹)?
- 5.What is the difference between the compound interest and the simple interest on ₹15000 at 8% per year for 2 years (in ₹)?
- 6.Find the compound interest on ₹11300 at 5% per year for 1 year, compounded every year (in ₹).
- 7.What is the difference between the compound interest and the simple interest on ₹35300 at 20% per year for 2 years (in ₹)?
- 8.Find the compound interest on ₹15500 at 15% per year for 1 year, compounded every year (in ₹).
- 9.What is the difference between the compound interest and the simple interest on ₹56800 at 5% per year for 2 years (in ₹)?
- 10.A town has 22600 people. The population grows by 25% every year. What will the population be after 1 year?
- 11.What amount will ₹38000 grow to in 1 year at 8% per year compound interest (in ₹)?
- 12.Find the compound interest on ₹23400 at 20% per year for 1 year, compounded every year (in ₹).
- 13.What is the difference between the compound interest and the simple interest on ₹22400 at 20% per year for 2 years (in ₹)?
- 14.A town has 35700 people. The population grows by 8% every year. What will the population be after 1 year?
- 15.What amount will ₹34900 grow to in 1 year at 25% per year compound interest (in ₹)?
- 16.A town has 30600 people. The population grows by 4% every year. What will the population be after 1 year?
- 17.A town has 56000 people. The population grows by 25% every year. What will the population be after 2 years?
- 18.A scooter is worth ₹5400. Its value falls by 15% every year. What will it be worth after 1 year (in ₹)?
- 19.Find the compound interest on ₹32000 at 5% per year for 3 years, compounded every year (in ₹).
- 20.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
- 21.A town has 3400 people. The population grows by 10% every year. What will the population be after 1 year?
- 22.Find the compound interest on ₹16000 at 25% per year for 3 years, compounded every year (in ₹).
- 23.What amount will ₹9400 grow to in 1 year at 15% per year compound interest (in ₹)?
- 24.What is the difference between the compound interest and the simple interest on ₹18100 at 10% per year for 2 years (in ₹)?
- 25.Find the compound interest on ₹42900 at 5% per year for 1 year, compounded every year (in ₹).
- 26.Find the compound interest on ₹19700 at 25% per year for 1 year, compounded every year (in ₹).
- 27.A scooter is worth ₹10900. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
- 28.A town has 56100 people. The population grows by 4% every year. What will the population be after 1 year?
- 29.What amount will ₹48000 grow to in 3 years at 20% per year compound interest (in ₹)?
- 30.Find the compound interest on ₹35500 at 20% per year for 3 years, compounded every year (in ₹).
- 31.What amount will ₹54600 grow to in 1 year at 5% per year compound interest (in ₹)?
- 32.What amount will ₹53000 grow to in 3 years at 10% per year compound interest (in ₹)?
- 33.Find the compound interest on ₹3200 at 25% per year for 3 years, compounded every year (in ₹).
- 34.A scooter is worth ₹44000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
- 35.Find the compound interest on ₹28100 at 4% per year for 1 year, compounded every year (in ₹).
- 36.A town has 56000 people. The population grows by 25% every year. What will the population be after 3 years?
- 37.What amount will ₹49900 grow to in 2 years at 10% per year compound interest (in ₹)?
- 38.Find the compound interest on ₹39500 at 12% per year for 1 year, compounded every year (in ₹).
- 39.Find the compound interest on ₹16900 at 20% per year for 1 year, compounded every year (in ₹).
- 40.What amount will ₹34200 grow to in 1 year at 12% per year compound interest (in ₹)?
Answer key
- 1624
- 5500
- 2544
- 24750
- 96
- 565
- 1412
- 2325
- 142
- 28250
- 41040
- 4680
- 896
- 38556
- 43625
- 31824
- 87500
- 4590
- 5044
- 9261
- 3740
- 15250
- 10810
- 181
- 2145
- 4925
- 10464
- 58344
- 82944
- 25844
- 57330
- 70543
- 3050
- 22528
- 1124
- 109375
- 60379
- 4740
- 3380
- 38304
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