Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 796 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.A scooter is worth ₹35200. Its value falls by 25% every year. What will it be worth after 3 years (in ₹)?
2. 2.What is the difference between the compound interest and the simple interest on ₹17500 at 8% per year for 2 years (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹8800 at 15% per year for 2 years (in ₹)?
4. 4.What amount will ₹50600 grow to in 1 year at 5% per year compound interest (in ₹)?
5. 5.Find the compound interest on ₹6500 at 8% per year for 1 year, compounded every year (in ₹).
6. 6.What is the difference between the compound interest and the simple interest on ₹46000 at 25% per year for 2 years (in ₹)?
7. 7.Find the compound interest on ₹8000 at 15% per year for 3 years, compounded every year (in ₹).
8. 8.A scooter is worth ₹40000. Its value falls by 4% every year. What will it be worth after 2 years (in ₹)?
9. 9.What amount will ₹24700 grow to in 1 year at 5% per year compound interest (in ₹)?
10. 10.Find the compound interest on ₹38500 at 8% per year for 1 year, compounded every year (in ₹).
11. 11.Find the compound interest on ₹11500 at 20% per year for 3 years, compounded every year (in ₹).
12. 12.A town has 2500 people. The population grows by 8% every year. What will the population be after 2 years?
13. 13.What amount will ₹27500 grow to in 2 years at 4% per year compound interest (in ₹)?
14. 14.A town has 57500 people. The population grows by 4% every year. What will the population be after 2 years?
15. 15.Find the compound interest on ₹15500 at 20% per year for 3 years, compounded every year (in ₹).
16. 16.A town has 13000 people. The population grows by 20% every year. What will the population be after 3 years?
17. 17.What is the difference between the compound interest and the simple interest on ₹35000 at 4% per year for 2 years (in ₹)?
18. 18.What amount will ₹32400 grow to in 2 years at 5% per year compound interest (in ₹)?
19. 19.What amount will ₹43600 grow to in 2 years at 15% per year compound interest (in ₹)?
20. 20.Find the compound interest on ₹25800 at 10% per year for 2 years, compounded every year (in ₹).
21. 21.Find the compound interest on ₹47300 at 20% per year for 1 year, compounded every year (in ₹).
22. 22.Find the compound interest on ₹31400 at 12% per year for 1 year, compounded every year (in ₹).
23. 23.What amount will ₹8000 grow to in 3 years at 5% per year compound interest (in ₹)?
24. 24.A scooter is worth ₹38800. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
25. 25.Find the compound interest on ₹30400 at 25% per year for 3 years, compounded every year (in ₹).
26. 26.What is the difference between the compound interest and the simple interest on ₹51000 at 20% per year for 2 years (in ₹)?
27. 27.What is the difference between the compound interest and the simple interest on ₹11600 at 5% per year for 2 years (in ₹)?
28. 28.Find the compound interest on ₹56000 at 5% per year for 3 years, compounded every year (in ₹).
29. 29.A scooter is worth ₹45000. Its value falls by 8% every year. What will it be worth after 2 years (in ₹)?
30. 30.Find the compound interest on ₹45700 at 15% per year for 1 year, compounded every year (in ₹).
31. 31.What amount will ₹11800 grow to in 2 years at 10% per year compound interest (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹3800 at 10% per year for 2 years (in ₹)?
33. 33.A town has 14000 people. The population grows by 25% every year. What will the population be after 2 years?
34. 34.A scooter is worth ₹35400. Its value falls by 25% every year. What will it be worth after 1 year (in ₹)?
35. 35.Find the compound interest on ₹58200 at 10% per year for 1 year, compounded every year (in ₹).
36. 36.Find the compound interest on ₹60000 at 15% per year for 2 years, compounded every year (in ₹).
37. 37.A scooter is worth ₹45000. Its value falls by 20% every year. What will it be worth after 1 year (in ₹)?
38. 38.Find the compound interest on ₹38100 at 20% per year for 1 year, compounded every year (in ₹).
39. 39.What amount will ₹8000 grow to in 3 years at 15% per year compound interest (in ₹)?
40. 40.Find the compound interest on ₹35800 at 10% per year for 1 year, compounded every year (in ₹).

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