Class 8 Maths Worksheet: Compound Interest

Maths worksheets lesson 63: Compound interest · Set 80 · 40 sums

The method (Grow it every year): Year by year: new amount = amount × (100 + R) ÷ 100. Amount after T years = P × (1 + R/100)ᵀ; compound interest = amount − P. A value falling by R% each year: × (100 − R) ÷ 100 every year. For 2 years, CI − SI = P × R × R ÷ 10000.

1. 1.What is the difference between the compound interest and the simple interest on ₹42500 at 8% per year for 2 years (in ₹)?
2. 2.What amount will ₹38400 grow to in 3 years at 25% per year compound interest (in ₹)?
3. 3.What is the difference between the compound interest and the simple interest on ₹43200 at 5% per year for 2 years (in ₹)?
4. 4.A scooter is worth ₹25200. Its value falls by 5% every year. What will it be worth after 2 years (in ₹)?
5. 5.Find the compound interest on ₹25200 at 15% per year for 2 years, compounded every year (in ₹).
6. 6.What amount will ₹10300 grow to in 1 year at 5% per year compound interest (in ₹)?
7. 7.Find the compound interest on ₹60000 at 4% per year for 2 years, compounded every year (in ₹).
8. 8.A town has 35000 people. The population grows by 4% every year. What will the population be after 2 years?
9. 9.What is the difference between the compound interest and the simple interest on ₹9200 at 20% per year for 2 years (in ₹)?
10. 10.A scooter is worth ₹35400. Its value falls by 4% every year. What will it be worth after 1 year (in ₹)?
11. 11.What is the difference between the compound interest and the simple interest on ₹34000 at 25% per year for 2 years (in ₹)?
12. 12.What amount will ₹12800 grow to in 2 years at 5% per year compound interest (in ₹)?
13. 13.A scooter is worth ₹24000. Its value falls by 20% every year. What will it be worth after 3 years (in ₹)?
14. 14.What is the difference between the compound interest and the simple interest on ₹17300 at 10% per year for 2 years (in ₹)?
15. 15.A town has 13400 people. The population grows by 10% every year. What will the population be after 2 years?
16. 16.A town has 42800 people. The population grows by 4% every year. What will the population be after 1 year?
17. 17.What is the difference between the compound interest and the simple interest on ₹11100 at 20% per year for 2 years (in ₹)?
18. 18.Find the compound interest on ₹34800 at 12% per year for 1 year, compounded every year (in ₹).
19. 19.Find the compound interest on ₹58900 at 20% per year for 1 year, compounded every year (in ₹).
20. 20.What is the difference between the compound interest and the simple interest on ₹35000 at 12% per year for 2 years (in ₹)?
21. 21.What is the difference between the compound interest and the simple interest on ₹22400 at 5% per year for 2 years (in ₹)?
22. 22.A town has 13000 people. The population grows by 20% every year. What will the population be after 3 years?
23. 23.A town has 33000 people. The population grows by 10% every year. What will the population be after 3 years?
24. 24.A town has 40300 people. The population grows by 15% every year. What will the population be after 1 year?
25. 25.A scooter is worth ₹15000. Its value falls by 20% every year. What will it be worth after 2 years (in ₹)?
26. 26.What amount will ₹55700 grow to in 1 year at 5% per year compound interest (in ₹)?
27. 27.A scooter is worth ₹12800. Its value falls by 10% every year. What will it be worth after 1 year (in ₹)?
28. 28.A town has 9500 people. The population grows by 5% every year. What will the population be after 1 year?
29. 29.What amount will ₹33500 grow to in 1 year at 8% per year compound interest (in ₹)?
30. 30.Find the compound interest on ₹35000 at 12% per year for 2 years, compounded every year (in ₹).
31. 31.What amount will ₹17500 grow to in 2 years at 4% per year compound interest (in ₹)?
32. 32.What is the difference between the compound interest and the simple interest on ₹55600 at 25% per year for 2 years (in ₹)?
33. 33.A town has 2500 people. The population grows by 20% every year. What will the population be after 2 years?
34. 34.Find the compound interest on ₹8000 at 5% per year for 3 years, compounded every year (in ₹).
35. 35.A town has 27500 people. The population grows by 10% every year. What will the population be after 2 years?
36. 36.A town has 60000 people. The population grows by 4% every year. What will the population be after 2 years?
37. 37.Find the compound interest on ₹22000 at 20% per year for 3 years, compounded every year (in ₹).
38. 38.Find the compound interest on ₹42700 at 20% per year for 2 years, compounded every year (in ₹).
39. 39.What is the difference between the compound interest and the simple interest on ₹27500 at 4% per year for 2 years (in ₹)?
40. 40.Find the compound interest on ₹42100 at 5% per year for 1 year, compounded every year (in ₹).

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